SQL/ Oracle 中给定当前日期的 90 个日历日期（往回看）的滚动总和
Rolling Sum over 90 Calendar date (look back) from given current date in SQL/ Oracle
**Calender_Date** **Customer_ID** **Amount**
01-Jan-21 20211003 59
01-Jan-21 20211005 100
27-Jan-21 20211003 25
25-Feb-21 20211003 188
23-Mar-21 20211005 67
24-Apr-21 20211009 43
25-May-21 20211013 21
26-May-21 20211013 89
11-Jul-21 20211009 65
28-Aug-21 20211003 90
需要： 考虑 Customer_ID - 超过 90 个日历回顾日期的滚动总和（从每个给定的当前日期开始）。
OutPut 要求或期望的结果
**Calender_Date** **Customer_ID** **Amount** **SumofLookbackRolling90DayAmount**
1-Jan-21 20211003 59 59
1-Jan-21 20211005 100 100
27-Jan-21 20211003 25 84
25-Feb-21 20211003 188 272
23-Mar-21 20211005 67 167
24-Apr-21 20211009 43 43
25-May-21 20211013 21 21
26-May-21 20211013 89 110
11-Jul-21 20211009 65 108
28-Aug-21 20211003 90 90
您可以使用范围为 window:
的解析函数
SELECT t.*,
SUM(amount) OVER (
PARTITION BY customer_id
ORDER BY calendar_date
RANGE BETWEEN INTERVAL '90' DAY PRECEDING
AND INTERVAL '0' DAY FOLLOWING
) AS rolling_sum
FROM table_name t
其中，对于您的示例数据：
CREATE TABLE table_name (Calendar_Date, Customer_ID, Amount) AS
SELECT DATE '2021-01-01', 20211003, 59 FROM DUAL UNION ALL
SELECT DATE '2021-01-01', 20211005, 100 FROM DUAL UNION ALL
SELECT DATE '2021-01-27', 20211003, 25 FROM DUAL UNION ALL
SELECT DATE '2021-02-25', 20211003, 188 FROM DUAL UNION ALL
SELECT DATE '2021-03-23', 20211005, 67 FROM DUAL UNION ALL
SELECT DATE '2021-04-24', 20211009, 43 FROM DUAL UNION ALL
SELECT DATE '2021-05-25', 20211013, 21 FROM DUAL UNION ALL
SELECT DATE '2021-05-26', 20211013, 89 FROM DUAL UNION ALL
SELECT DATE '2021-07-11', 20211009, 65 FROM DUAL UNION ALL
SELECT DATE '2021-08-28', 20211003, 90 FROM DUAL;
输出：
CALENDAR_DATE
CUSTOMER_ID
AMOUNT
ROLLING_SUM
01-JAN-21
20211003
59
59
27-JAN-21
20211003
25
84
25-FEB-21
20211003
188
272
28-AUG-21
20211003
90
90
01-JAN-21
20211005
100
100
23-MAR-21
20211005
67
167
24-APR-21
20211009
43
43
11-JUL-21
20211009
65
108
25-MAY-21
20211013
21
21
26-MAY-21
20211013
89
110
db<>fiddle here
**Calender_Date** **Customer_ID** **Amount**
01-Jan-21 20211003 59
01-Jan-21 20211005 100
27-Jan-21 20211003 25
25-Feb-21 20211003 188
23-Mar-21 20211005 67
24-Apr-21 20211009 43
25-May-21 20211013 21
26-May-21 20211013 89
11-Jul-21 20211009 65
28-Aug-21 20211003 90
需要： 考虑 Customer_ID - 超过 90 个日历回顾日期的滚动总和（从每个给定的当前日期开始）。
OutPut 要求或期望的结果
**Calender_Date** **Customer_ID** **Amount** **SumofLookbackRolling90DayAmount**
1-Jan-21 20211003 59 59
1-Jan-21 20211005 100 100
27-Jan-21 20211003 25 84
25-Feb-21 20211003 188 272
23-Mar-21 20211005 67 167
24-Apr-21 20211009 43 43
25-May-21 20211013 21 21
26-May-21 20211013 89 110
11-Jul-21 20211009 65 108
28-Aug-21 20211003 90 90
您可以使用范围为 window:
的解析函数SELECT t.*,
SUM(amount) OVER (
PARTITION BY customer_id
ORDER BY calendar_date
RANGE BETWEEN INTERVAL '90' DAY PRECEDING
AND INTERVAL '0' DAY FOLLOWING
) AS rolling_sum
FROM table_name t
其中，对于您的示例数据：
CREATE TABLE table_name (Calendar_Date, Customer_ID, Amount) AS
SELECT DATE '2021-01-01', 20211003, 59 FROM DUAL UNION ALL
SELECT DATE '2021-01-01', 20211005, 100 FROM DUAL UNION ALL
SELECT DATE '2021-01-27', 20211003, 25 FROM DUAL UNION ALL
SELECT DATE '2021-02-25', 20211003, 188 FROM DUAL UNION ALL
SELECT DATE '2021-03-23', 20211005, 67 FROM DUAL UNION ALL
SELECT DATE '2021-04-24', 20211009, 43 FROM DUAL UNION ALL
SELECT DATE '2021-05-25', 20211013, 21 FROM DUAL UNION ALL
SELECT DATE '2021-05-26', 20211013, 89 FROM DUAL UNION ALL
SELECT DATE '2021-07-11', 20211009, 65 FROM DUAL UNION ALL
SELECT DATE '2021-08-28', 20211003, 90 FROM DUAL;
输出：
CALENDAR_DATE CUSTOMER_ID AMOUNT ROLLING_SUM 01-JAN-21 20211003 59 59 27-JAN-21 20211003 25 84 25-FEB-21 20211003 188 272 28-AUG-21 20211003 90 90 01-JAN-21 20211005 100 100 23-MAR-21 20211005 67 167 24-APR-21 20211009 43 43 11-JUL-21 20211009 65 108 25-MAY-21 20211013 21 21 26-MAY-21 20211013 89 110
db<>fiddle here