Select 列中的子字符串，但每条记录都有不同的模式

Question

我的每条记录都有不同字符串模式的列，我们称之为 [描述]。这是记录示例

  [Description]
 -qwetw MANN/1234556/DATE/030621/B/C/ACC/DIFF+AA11000532
 -qwerty 123456789/06/29/2021/ACC./DONE/CLOSED+06+AA11001234
 -qwert 123456789101213/-/BACK/300621/Rekening/Tutup+06+ZZZ21001123A

我只想选择最后一个数字顺序 - 所以输出将是：

[Description]
 -11000532
 -11001234
 -21001123

有什么函数怎么获取吗？

谢谢

Answer 1

您的示例很棘手，因为它也将字母作为订单号的一部分。

我假设您的数据类型是 VARCHAR(4000)，因此，我在末尾应用了子字符串 4000，以使其最终更简单。

DECLARE @table table(Description varchar(4000))

  insert into @table values

('-qwetw MANN/1234556/DATE/030621/B/C/ACC/DIFF+AA11000532')
,('-qwert 123456789101213/-/BACK/300621/Rekening/Tutup+06+ZZZ21001123A')
,('-qwerty 123456789/06/29/2021/ACC./DONE/CLOSED+06+AA11001234');

SELECT SUBSTRING(REVERSE(SUBSTRING(REVERSE(Description),1,CHARINDEX('+',REVERSE(Description)))),PATINDEX('%[1-9]%',REVERSE(SUBSTRING(REVERSE(Description),1,CHARINDEX('+',REVERSE(Description))))),4000) as ordernumber FROM @table

ordernumber
11000532
21001123A
11001234

Answer 2

请尝试以下解决方案。

第一个解决方案适用于 SQL Server 2017 及更高版本。

它通过执行以下步骤来工作：

它正在将列值标记为 XML。
最后一个标记是我们的目标，即 (/root/r[last()]/text())[1]
TRIM() 删除不需要的字符。

第二个解决方案适用于 SQL Server 2012。它涉及更多。

SQL 2017

-- DDL and sample data population, start
DECLARE @tbl TABLE (ID INT IDENTITY PRIMARY KEY, Tokens VARCHAR(4000));
INSERT INTO @tbl VALUES
('-qwetw MANN/1234556/DATE/030621/B/C/ACC/DIFF+AA11000532'),
('-qwert 123456789101213/-/BACK/300621/Rekening/Tutup+06+ZZZ21001123A'),
('-qwerty 123456789/06/29/2021/ACC./DONE/CLOSED+06+AA11001234');
-- DDL and sample data population, end

DECLARE @separator CHAR(1) = '+'
    , @CharsToRemove VARCHAR(100) = 'AZ';

SELECT ID, tokens
    , TRIM(@CharsToRemove FROM token) AS Result
FROM @tbl
CROSS APPLY (VALUES (TRY_CAST('<root><r><![CDATA[' + 
      REPLACE(tokens, @separator, ']]></r><r><![CDATA[') + 
      ']]></r></root>' AS XML))) AS t(c)
CROSS APPLY (VALUES (c.value('(/root/r[last()]/text())[1]', 'VARCHAR(256)'))) AS t2(token);

SQL 2012

SELECT ID, tokens
    , (
   SELECT SUBSTRING(token, number, 1)
   FROM @tbl AS c
      CROSS APPLY (
         SELECT DISTINCT number
         FROM master..spt_values
         WHERE number BETWEEN 1 AND LEN(token)
      ) V
   WHERE c.ID = p.ID
   FOR XML PATH('r'), TYPE, ROOT('root')
)
.query('for $x in /root/r
        return if (xs:int($x) instance of xs:int) then $x
         else ()') 
.query('/r/text()').value('.', 'BIGINT') AS Result
FROM @tbl AS p
CROSS APPLY (VALUES (TRY_CAST('<root><r><![CDATA[' + 
      REPLACE(tokens, @separator, ']]></r><r><![CDATA[') + 
      ']]></r></root>' AS XML))) AS t(c)
CROSS APPLY (VALUES (c.value('(/root/r[last()]/text())[1]', 'VARCHAR(256)'))) AS t2(token);

输出

+----+---------------------------------------------------------------------+----------+
| ID |                               tokens                                |  Result  |
+----+---------------------------------------------------------------------+----------+
|  1 | -qwetw MANN/1234556/DATE/030621/B/C/ACC/DIFF+AA11000532             | 11000532 |
|  2 | -qwert 123456789101213/-/BACK/300621/Rekening/Tutup+06+ZZZ21001123A | 21001123 |
|  3 | -qwerty 123456789/06/29/2021/ACC./DONE/CLOSED+06+AA11001234         | 11001234 |
+----+---------------------------------------------------------------------+----------+

Select 列中的子字符串，但每条记录都有不同的模式

Select substring from column but each record has different pattern

sql

tsql

sql-server

sql-server-2012