如何在函数中平嵌套元组参数?
How to flat nest tuple parameter in function?
我有一个需要参数 (Int, (Int, Int)) => Int
的函数 g
和一个平面函数 f0
(Int, Int, Int) => Int
我想构造一个函数ft
,它可以将g
的参数扁平化为f0
。
这是示例:
val f0: ((Int, Int, Int)) => Int = (x: (Int, Int, Int)) => {
x._1 + x._2 + x._3
}
def g(f: ((Int, (Int, Int))) => Int): Int = f(1,(2,3))
def ft(f: ((Int, Int, Int)) => Int): ((Int, (Int, Int))) => Int = (p: (Int, (Int, Int))) => {
f(p._1, p._2._1, p._2._2)
}
// invoke it
g(ft(f0))
但是我有几个嵌套元组的函数,我不想手动转换每个。例如,((Int, Int), (Int, Int)) => Int
到 (Int, Int, Int, Int) => Int
Here说可以用shapeless
那么新的函数就想
import shapeless._
import ops.tuple.FlatMapper
trait LowPriorityFlatten extends Poly1 {
implicit def default[T] = at[T](Tuple1(_))
}
object flatten extends LowPriorityFlatten {
implicit def caseTuple[P <: Product](implicit lfm: Lazy[FlatMapper[P, flatten.type]]) =
at[P](lfm.value(_))
}
def ft(f: ((Int, Int, Int)) => Int): ((Int, (Int, Int))) => Int = (p: (Int, (Int, Int))) => {
val a: (Int, Int, Int) = flatten(p).asInstanceOf[(Int, Int, Int)]
f(a)
}
上面的代码有两个问题:
- 如何定义函数
ft[A, B, C](f: A => C): B
其中 A
是 B
的扁平类型?
flatten(p)
将产品类型 FlatMapper.this.Out
和错过类型,所以我使用 asInstanceOf
在这里转换类型。
那么,如何编写一个函数来展平参数中任何类型的嵌套元组?
以下代码适用于 Scala 3:
scala> type Flat[T <: Tuple] <: Tuple = T match
| case EmptyTuple => EmptyTuple
| case h *: t => h match
| case Tuple => Tuple.Concat[Flat[h], Flat[t]]
| case _ => h *: Flat[t]
|
scala> def flat[T <: Tuple](v: T): Flat[T] = (v match
| case e: EmptyTuple => e
| case h *: ts => h match
| case t: Tuple => flat(t) ++ flat(ts)
| case _ => h *: flat(ts)).asInstanceOf[Flat[T]]
def flat[T <: Tuple](v: T): Flat[T]
scala> def ft[A <: Tuple, C](f: Flat[A] => C): A => C = a => f(flat(a))
def ft[A <: Tuple, C](f: Flat[A] => C): A => C
scala> val f0: ((Int, Int, Int)) => Int = x => x._1 + x._2 + x._3
scala> def g0(f: ((Int, (Int, Int))) => Int): Int = f(1,(2,3))
scala> g0(ft(f0))
val res0: Int = 6
编辑: 添加 scala2 的版本:
import shapeless._
import ops.tuple.FlatMapper
import syntax.std.tuple._
trait LowPriorityFlat extends Poly1 {
implicit def default[T] = at[T](Tuple1(_))
}
object Flat extends LowPriorityFlat {
implicit def caseTuple[P <: Product](implicit fm: FlatMapper[P, Flat.type]) =
at[P](_.flatMap(Flat))
}
type F[A, B] = FlatMapper.Aux[A, Flat.type, B]
def flatTup[T <: Product](t: T)(implicit lfm: FlatMapper[T, Flat.type]): lfm.Out =
FlatMapper[T, Flat.type].apply(t)
def flatFun[A <: Product, B <: Product, C](f: B => C)
(implicit lfm: F[A, B]): A => C =
a => f(flatTup(a))
val f0: ((Int, Double, Int, Double)) => Double = { case(i1, d1, i2, d2) => (i1 + i2) / (d1 + d2) }
def g0(f: (((Int, Double), (Int, Double))) => Double): Double = f((1, 2.0), (3, 4.0))
val r0 = g0(flatFun(f0))
我有一个需要参数 (Int, (Int, Int)) => Int
的函数 g
和一个平面函数 f0
(Int, Int, Int) => Int
我想构造一个函数ft
,它可以将g
的参数扁平化为f0
。
这是示例:
val f0: ((Int, Int, Int)) => Int = (x: (Int, Int, Int)) => {
x._1 + x._2 + x._3
}
def g(f: ((Int, (Int, Int))) => Int): Int = f(1,(2,3))
def ft(f: ((Int, Int, Int)) => Int): ((Int, (Int, Int))) => Int = (p: (Int, (Int, Int))) => {
f(p._1, p._2._1, p._2._2)
}
// invoke it
g(ft(f0))
但是我有几个嵌套元组的函数,我不想手动转换每个。例如,((Int, Int), (Int, Int)) => Int
到 (Int, Int, Int, Int) => Int
Here说可以用shapeless
那么新的函数就想
import shapeless._
import ops.tuple.FlatMapper
trait LowPriorityFlatten extends Poly1 {
implicit def default[T] = at[T](Tuple1(_))
}
object flatten extends LowPriorityFlatten {
implicit def caseTuple[P <: Product](implicit lfm: Lazy[FlatMapper[P, flatten.type]]) =
at[P](lfm.value(_))
}
def ft(f: ((Int, Int, Int)) => Int): ((Int, (Int, Int))) => Int = (p: (Int, (Int, Int))) => {
val a: (Int, Int, Int) = flatten(p).asInstanceOf[(Int, Int, Int)]
f(a)
}
上面的代码有两个问题:
- 如何定义函数
ft[A, B, C](f: A => C): B
其中A
是B
的扁平类型? flatten(p)
将产品类型FlatMapper.this.Out
和错过类型,所以我使用asInstanceOf
在这里转换类型。
那么,如何编写一个函数来展平参数中任何类型的嵌套元组?
以下代码适用于 Scala 3:
scala> type Flat[T <: Tuple] <: Tuple = T match
| case EmptyTuple => EmptyTuple
| case h *: t => h match
| case Tuple => Tuple.Concat[Flat[h], Flat[t]]
| case _ => h *: Flat[t]
|
scala> def flat[T <: Tuple](v: T): Flat[T] = (v match
| case e: EmptyTuple => e
| case h *: ts => h match
| case t: Tuple => flat(t) ++ flat(ts)
| case _ => h *: flat(ts)).asInstanceOf[Flat[T]]
def flat[T <: Tuple](v: T): Flat[T]
scala> def ft[A <: Tuple, C](f: Flat[A] => C): A => C = a => f(flat(a))
def ft[A <: Tuple, C](f: Flat[A] => C): A => C
scala> val f0: ((Int, Int, Int)) => Int = x => x._1 + x._2 + x._3
scala> def g0(f: ((Int, (Int, Int))) => Int): Int = f(1,(2,3))
scala> g0(ft(f0))
val res0: Int = 6
编辑: 添加 scala2 的版本:
import shapeless._
import ops.tuple.FlatMapper
import syntax.std.tuple._
trait LowPriorityFlat extends Poly1 {
implicit def default[T] = at[T](Tuple1(_))
}
object Flat extends LowPriorityFlat {
implicit def caseTuple[P <: Product](implicit fm: FlatMapper[P, Flat.type]) =
at[P](_.flatMap(Flat))
}
type F[A, B] = FlatMapper.Aux[A, Flat.type, B]
def flatTup[T <: Product](t: T)(implicit lfm: FlatMapper[T, Flat.type]): lfm.Out =
FlatMapper[T, Flat.type].apply(t)
def flatFun[A <: Product, B <: Product, C](f: B => C)
(implicit lfm: F[A, B]): A => C =
a => f(flatTup(a))
val f0: ((Int, Double, Int, Double)) => Double = { case(i1, d1, i2, d2) => (i1 + i2) / (d1 + d2) }
def g0(f: (((Int, Double), (Int, Double))) => Double): Double = f((1, 2.0), (3, 4.0))
val r0 = g0(flatFun(f0))