是否可以在不对当前状态使用条件语句的情况下使用状态机？

Question

我想使用当前状态映射到当前屏幕的状态机。我正在使用 svelte with xstate.
以字符串为类型的示例：
App.svelte

<script>
    import { interpret } from "xstate";
    import { toggleMachine } from "./machine";

    const toggleService = interpret(toggleMachine).start();
</script>

<button on:click={() => toggleService.send("TOGGLE")}>
    <p>{$toggleService.value}</p>
</button>

machine.js

import { createMachine } from 'xstate';

// This machine is completely decoupled from Svelte
export const toggleMachine = createMachine({
    id: 'toggle',
    initial: 'LOGIN',
    states: {
        LOBBY: {
            on: { TOGGLE: 'LOGIN' }
        },
        LOGIN: {
            on: { TOGGLE: 'LOBBY' }
        }
    }
});

如何使用 svelte 组件而不是字符串来做同样的事情？
而不是 <p>{$toggleService.value}</p> 这样的东西 <$toggleService.value />

编辑：我尝试过的：

创建大厅和登录 svelte 组件 Login.svelte

<script lang="ts">
</script>

<main>
    <h1>Login</h1>
</main>

<style>
</style>

Lobby.svelte

<script lang="ts">
</script>

<main>
    <h1>Lobby</h1>
</main>

<style>
</style>

在machine.js

import { createMachine } from 'xstate';
import Login from './Login.svelte'
import Lobby from './Lobby.svelte'
// This machine is completely decoupled from Svelte
export const toggleMachine = createMachine({
    id: 'toggle',
    initial: Login,
    states: {
        Login: {
            on: { TOGGLE: Lobby }
        },
        Lobby: {
            on: { TOGGLE: Login }
        }
    }
});

在App.svelte中使用状态机 App.svelte

<script>
    import { interpret } from "xstate";
    import { toggleMachine } from "./machine";

    const toggleService = interpret(toggleMachine).start();
</script>

<button on:click={() => toggleService.send("TOGGLE")}>
    <$toggleService.value />
</button>

我收到错误：

[!] (plugin svelte) ParseError: Expected valid tag name
src/App.svelte
 7: 
 8: <button on:click={() => toggleService.send("TOGGLE")}>
 9:   <$toggleService.value />
       ^
10: </button>
ParseError: Expected valid tag name
    at error (/home/walde/projects/svelte/xstate/node_modules/svelte/src/compiler/utils/error.ts:25:16)
    at Parser.error (/home/walde/projects/svelte/xstate/node_modules/svelte/src/compiler/parse/index.ts:101:3)
    at read_tag_name (/home/walde/projects/svelte/xstate/node_modules/svelte/src/compiler/parse/state/tag.ts:267:10)
    at tag (/home/walde/projects/svelte/xstate/node_modules/svelte/src/compiler/parse/state/tag.ts:77:15)
    at new Parser (/home/walde/projects/svelte/xstate/node_modules/svelte/src/compiler/parse/index.ts:53:12)
    at parse (/home/walde/projects/svelte/xstate/node_modules/svelte/src/compiler/parse/index.ts:218:17)
    at compile (/home/walde/projects/svelte/xstate/node_modules/svelte/src/compiler/compile/index.ts:93:14)
    at Object.transform (/home/walde/projects/svelte/xstate/node_modules/rollup-plugin-svelte/index.js:111:21)
    at /home/walde/projects/svelte/xstate/node_modules/rollup/dist/shared/rollup.js:20218:25

Answer 1

我不能代表 xstate 部分，但最后一个片段肯定不起作用。您不能像这样动态声明标签。但是你可以为此使用特殊的 <svelte:component> 元素：

<script>
    import { interpret } from "xstate";
    import { toggleMachine } from "./machine";

    const toggleService = interpret(toggleMachine).start();
</script>

<button on:click={() => toggleService.send("TOGGLE")}>
    Toggle me
</button>
<svelte:component this={$toggleService.value} />

文档：https://svelte.dev/docs#svelte_component

Answer 2

感谢 dummdidumm 帮助解决了 svelte 部分的问题。

如何在不写条件语句的情况下一起使用svelte和xstate的问题的完整解决方案是：

将组件绑定到状态机的上下文

<svelte:component this={$toggleService.context.component} />

在进入新状态时将状态机上下文更改为与当前状态匹配。

        Login: {
            on: { TOGGLE: "Lobby" },
            entry: assign({ component: (ctx) => ctx.component = Login }),
        }

完整的工作示例：
App.svelte

<script>
    import { interpret } from "xstate";
    import { toggleMachine } from "./machine";
    const toggleService = interpret(toggleMachine).start();
</script>

<button on:click={() => toggleService.send("TOGGLE")}>
    {$toggleService.value}
</button>
<svelte:component this={$toggleService.context.component} />

Lobby.svelte

<script lang="ts">
</script>
<main>
    <h1>SVELTE Lobby</h1>
</main>
<style>
</style>

Login.svelte

<script lang="ts">
</script>
<main>
    <h1>SVELTE Login</h1>
</main>
<style>
</style>

machine.js

import { createMachine, assign } from 'xstate';
import Login from './Login.svelte'
import Lobby from './Lobby.svelte'
export const toggleMachine = createMachine({
    id: 'toggle',
    initial: "Login",
    context: {
        component: Lobby
    },
    states: {
        Login: {
            on: { TOGGLE: "Lobby" },
            entry: assign({ component: (ctx) => ctx.component = Login }),
        },
        Lobby: {
            on: { TOGGLE: "Login" },
            entry: assign({ component: (ctx) => ctx.component = Lobby }),
        }
    }
});

是否可以在不对当前状态使用条件语句的情况下使用状态机？

Is it posible to use a State Machine without using Conditional Statements on the Current State?

javascript

user-interface

state-machine

svelte

xstate