寻找对 `UserConfigResponseModel` 的修改以声明正确的 `aws_api_gateway_method_response` 资源

Question

Reading this document for how to setup an AWS Transfer Family SFTP server 指定您需要 application/json UserConfigResponseModel 方法响应类型。通过 Web 控制台设置时，这是一种可能的配置

但是当我尝试在 Terraform 中创建相同的配置时，我遇到了

Error: Error creating API Gateway Method Response: BadRequestException: Invalid model identifier specified: UserConfigResponseModel

  on ../../../../module/data-platform-sftp/api_gateway.tf line 53, in resource "aws_api_gateway_method_response" "status_200":
  53: resource "aws_api_gateway_method_response" "status_200" {

地形声明为

resource "aws_api_gateway_method_response" "status_200" {
  rest_api_id   = aws_api_gateway_rest_api.reconciliation_auth.id
  resource_id   = aws_api_gateway_resource.config_path.id
  http_method = aws_api_gateway_method.config_get.http_method
  status_code = "200"

  response_models = {
    "application/json" = "UserConfigResponseModel"
  }
}

我想知道是否有可能找到所有有效的模型标识符，或者是否有人知道正确的语法来声明此 response_model。

第一次编辑

感谢@marcin 让我走上了正确的道路。我知道我需要做什么，但目前我还没有明确地知道如何做。

尝试一次

resource "aws_api_gateway_model" "status_200" {
  rest_api_id   = aws_api_gateway_rest_api.reconciliation_auth.id
  name         = "UserConfigResponseModel"
  description  = "a JSON schema that matches the documented schema here: https://aws.amazon.com/premiumsupport/knowledge-center/transfer-customize-identity-provider/"
  content_type = "application/json"

  schema = <<EOF
{"$schema":"http://json-schema.org/draft-04/schema#","title":"UserUserConfig","type":"object","properties":{"Role":{"type":"string"},"Policy":{"type":"string"},"HomeDirectory":{"type":"string"},"PublicKeys":{"type":"array","items":{"type":"string"}}}}
EOF
}

resource "aws_api_gateway_method_response" "status_200" {
  rest_api_id   = aws_api_gateway_rest_api.reconciliation_auth.id
  resource_id   = aws_api_gateway_resource.config_path.id
  http_method = aws_api_gateway_method.config_get.http_method
  status_code = "200"

  response_models = aws_api_gateway_model.status_200
}

导致

Error: Error creating API Gateway Method Response: BadRequestException: Invalid model identifier specified: {"$schema":"http://json-schema.org/draft-04/schema#","title":"UserUserConfig","type":"object","properties":{"Role":{"type":"string"},"Policy":{"type":"string"},"H
omeDirectory":{"type":"string"},"PublicKeys":{"type":"array","items":{"type":"string"}}}}


  on ../../../../module/data-platform-sftp/api_gateway.tf line 65, in resource "aws_api_gateway_method_response" "status_200":
  65: resource "aws_api_gateway_method_response" "status_200" {

尝试二

这导致正确的配置 enter image description here

Answer 1

您必须首先使用您提供的 api_gateway_model. The schema that you need is in the link 创建您的 UserConfigResponseModel。

寻找对 `UserConfigResponseModel` 的修改以声明正确的 `aws_api_gateway_method_response` 资源

Looking for Modification to `UserConfigResponseModel` To Declare a Correct `aws_api_gateway_method_response` resource

amazon-web-services

terraform

api-gateway

第一次编辑

尝试一次

尝试二