字符串中第一个字母的单词计数器不起作用

Question

我正在尝试让 Python 中的计数器按第一个字母对单词进行计数。我可以让它计算一切，包括空格。

例如，在下面的代码中，以 's' 开头的单词数是 4。我知道这一点，但我的程序给我 's' 作为 10，这是每个 's' 在字符串中。我如何让它只使用单词中的第一个字母？

from collections import Counter
my_str = "When I pronounce the word Future,\n the first syllable already belongs to the past.\n\n When I pronounce the word Silence,\n I destroy it.\n\n When I pronounce the word Nothing,\n I make something no nonbeing can hold.\n\n Wislawa Szymborska"
my_count = Counter(my_str.lower())
for word in [my_str]:
    my_count[word[0].lower()]+=1
print(my_count)

我的输出是：

Counter({' ': 37, 'e': 21, 'n': 19, 'o': 18, 't': 13, 'i': 12, 'h': 11, 'r': 11, 's': 10, 'w': 9, '\n': 9, 'a': 9, 'l': 8, 'd': 6, 'u': 5, 'c': 5, 'p': 4, 'y': 4, 'b': 4, 'g': 4, ',': 3, '.': 3, 'm': 3, 'f': 2, 'k': 2, 'z': 1})

Answer 1

试试这个：

from collections import Counter
from operator import itemgetter
my_str = "When I pronounce the word Future,\n the first syllable already belongs to the past.\n\n When I pronounce the word Silence,\n I destroy it.\n\n When I pronounce the word Nothing,\n I make something no nonbeing can hold.\n\n Wislawa Szymborska"
my_count = Counter(map(itemgetter(0), my_str.lower().split()))
print(my_count)

输出：

Counter({'w': 7, 'i': 6, 't': 6, 'p': 4, 's': 4, 'n': 3, 'f': 2, 'a': 1, 'b': 1, 'd': 1, 'm': 1, 'c': 1, 'h': 1})

Answer 2

使用列表理解和.split()-

from collections import Counter
my_str = "When I pronounce the word Future,\n the first syllable already belongs to the past.\n\n When I pronounce the word Silence,\n I destroy it.\n\n When I pronounce the word Nothing,\n I make something no nonbeing can hold.\n\n Wislawa Szymborska"

my_count = Counter([i[0].lower() for i in my_str.split()])

print(my_count)

字符串中第一个字母的单词计数器不起作用

Counter of words by first letter within string not working

python

string

counter