从 Python 中嵌套的 Json 中提取信息

Extract information from nested Json in Python

我有一个 dataset 包含嵌套的 json 对象。我希望从这个嵌套的 json 中提取信息并将其放入 python 中的 DataFrame 中。我使用了 json_normalize 方法,但在一定级别后无法解析。请帮忙。谢谢。

要“扁平化”嵌套的 json 文件,您可以使用以下函数:

def flatten_json(nested_json):       
    out = {}

    def flatten(x, name=''):
        if type(x) is dict:
            for a in x:
                flatten(x[a], name + a + '_')
        elif type(x) is list:
            i = 0
            for a in x:
                flatten(a, name + str(i) + '_')
                i += 1
        else:
            out[name[:-1]] = x

    flatten(nested_json)
    return out

假设您的 json 被称为 myjson:

df = pd.Series(flatten_json(myjson)).to_frame()

一直在开发一个可以扩展所有嵌入式列表和词典的功能。

from pathlib import Path

with open(Path.home().joinpath("Downloads").joinpath("Sample Json.txt")) as f: js = f.read()

def normalize(js, expand_all=False):
    df = pd.json_normalize(json.loads(js) if type(js) == str else js)
    # get first column that contains lists
    col = df.applymap(type).astype(str).eq("<class 'list'>").all().idxmax()
    # explode list and expand embedded dictionaries
    df = df.explode(col).reset_index(drop=True)
    df = df.drop(columns=[col]).join(df[col].apply(pd.Series), rsuffix=f".{col}")
    # any dictionary to expand?
    if df.applymap(type).astype(str).eq("<class 'dict'>").any().any():
        col = df.applymap(type).astype(str).eq("<class 'dict'>").all().idxmax()
        df = df.drop(columns=[col]).join(df[col].apply(pd.Series), rsuffix=f".{col}")

    # any lists left?
    while expand_all and df.applymap(type).astype(str).eq("<class 'list'>").any().any():
        df = normalize(df.to_dict("records"))
    return df

    
    
df = normalize(js, expand_all=True)

cfs ctin fldtr1 cfs3b flprdr1 dtcancel val inv_typ pos idt rchrg inum chksum num csamt samt rt txval camt iamt
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23 Y 03AA9 18-Aug-20 Y Jul-20 nan 41914 R 03 29-07-2020 N 2020-21/K-916 d112ad384eb291d49509bdf4a005d509424fefee4caf3443bc9726cf41665295 1801 0 3196.8 18 35520 3196.8 nan
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29 Y 03AD1Z1 13-Aug-20 Y Jul-20 nan 8968 R 03 01-07-2020 N B25 5b98b819ca14a377c9304e7eab21957152c4819e82e37f2619fb2c547fb84ba6 1801 0 684 18 7600 684 nan
30 Y 03AAO 10-Aug-20 Y Jul-20 nan 38940 R 03 13-07-2020 N TI/20-21/30 bae339e580c2ab9ffee90533650e4e2acdc47310230ed54aabbb96f89d3fc7c4 101 0 2970 18 33000 2970 0
31 Y 07AH1ZU 11-Aug-20 Y Jul-20 nan 13836.5 R 03 31-07-2020 N DELR/EXP/12176 cb34f329adcd88c9e8794db9892fe47bd0a7afc0373a20860de046934f7923fa 1 0 nan 18 11725.9 nan 2110.65
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