如何在 timedelta 中将秒数转换为以 HH:MM:SS 表示的时间

Question

我有一个数据框，我想在其中将持续时间（以秒为单位）添加到开始时间列以获得结束时间。开始时间和结束时间列为 datetime64[ns] 类型，而持续时间为 [int64] 类型

start-time,duration
2012-01-02 05:57:38,1168
2012-04-02 06:18:39,58

我首先将持续时间列转换为 timedelta 格式的 hh:mm:ss，以便我进行加法运算。 duration 列已成功转换为 timedelta，但显示为 1970-01-01T00:19:28Z。我怎样才能摆脱 1970 年的日期部分，只保留 hh:mm:ss 时间部分，但仍然是 timedelta 类型。

我试过以下

df['duration'] = df['duration'].astype('float64')
df['duration'] = pd.to_datetime(df['duration'], unit='s').dt.strftime("%H:%M:%S")
df['duration'] = pd.to_timedelta(df['duration'])
df['end-time'] = df['start-time'] + df['duration']

输出

start-time,end-time,duration
2012-04-02 05:57:38,2012-04-02 06:17:06,1970-01-01T00:19:28Z
2012-04-02 06:18:39,2012-04-02 06:19:37,1970-01-01T00:00:58Z

期望输出

start-time,end-time,duration
2012-01-02 05:57:38,2012-04-02 06:17:06,00:19:28
2012-04-02 06:18:39,2012-04-02 06:19:37,00:00:58

Answer 1

您不需要从 int -> float -> datetime -> timedelta 转换

你可以直接从 int seconds 到 timedelta

df['duration'] = pd.to_timedelta(df['duration'], unit='s')
df['end-time'] = df['start-time'] + df['duration']
df = df[['start-time','end-time','duration']]

输入

         start-time  duration
2012-01-02 05:57:38      1168
2012-04-02 06:18:39        58

输出

         start-time            end-time        duration
2012-01-02 05:57:38 2012-01-02 06:17:06 0 days 00:19:28
2012-04-02 06:18:39 2012-04-02 06:19:37 0 days 00:00:58

如何在 timedelta 中将秒数转换为以 HH:MM:SS 表示的时间

How to Convert Seconds to Time Expressed in HH:MM:SS in timedelta

python

timedelta

dataframe

pandas