如何访问活动作业中的延迟作业实例 - Rails 4.2

How to access Delayed Job instance inside Active Job - Rails 4.2

我在后台使用 delayed_job (4.0.6) 的 ActiveJob,我想找到一个计划的作业来删除它。

例如,如果我有

class MyClass

  def my_method
    perform_stuff
    MyJob.set(wait: 1.month.from_now).perform_later(current_user)
  end
end

然后,如果我编辑 MyClass 实例并再次调用 my_method,我想取消该作业并安排一个新作业。

按照此 post http://www.sitepoint.com/delayed-jobs-best-practices 中的建议,我向延迟作业添加了两列 Table:

table.integer :delayed_reference_id
table.string  :delayed_reference_type

add_index :delayed_jobs, [:delayed_reference_id],   :name => 'delayed_jobs_delayed_reference_id'
add_index :delayed_jobs, [:delayed_reference_type], :name => 'delayed_jobs_delayed_reference_type'

所以这样我可能会找到延迟的工作并将其销毁。但我想在 ActiveJob class 中执行此操作,以维护我项目中的作业模式。

我想做这样的事情:

class MyJob < ActiveJob::Base

  after_enqueue do |job|
    user = self.arguments.first
    job.delayed_reference_id = user.id,
    job.delayed_reference_type = "User" 
  end

  def perform(user)
    delete_previous_job_if_exists(user_id)
  end

  def delete_previous_job_if_exists(user_id)
    Delayed::Job.find_by(delayed_reference_id: 1, delayed_reference_type: 'User').delete
  end
end

但这不起作用。

有人遇到过这种问题吗?

两个变化: 1. 更新了 after_enqueue 回调,以便您可以更新 delayed_jobs table 直接 2. 修复了 delayed_reference_id 被硬编码为 1

的拼写错误

这应该有效:

class MyJob < ActiveJob::Base

  after_enqueue do |job|
    user = self.arguments.first
    delayed_job = Delayed::Job.find(job.provider_job_id)
    delayed_job.update(delayed_reference_id:user.id,delayed_reference_type:'User')
 end

  def perform(user)
    delete_previous_job_if_exists(user.id)
  end

  def delete_previous_job_if_exists(user_id)
    Delayed::Job.find_by(delayed_reference_id: user_id, delayed_reference_type: 'User').delete
  end
end