如何在 signals.py 文件中获取当前登录的用户?

How to get currently logged-in user in signals.py file?

我正在制作一个 todo 应用程序,其中一个功能是 的用户发送一封电子邮件 ]他的任务逾期了

views.py 文件的一部分:

from .models import Todo
from django.utils import timezone
from .signals import overdue

def index(request):
    ...
    overdue_tasks = Todo.objects.filter(time__lte=timezone.now())
    if overdue_tasks:
        overdue.send_robust(sender=Todo)
    ...
    return render(request, 'todo/index.html', {'overdue_tasks' : overdue_tasks })

signals.py 文件的一部分:

from django.dispatch import receiver, Signal
from .models import Todo
from django.core.mail import send_mail

overdue = Signal()
user_email = request.user.email

@receiver(overdue)
def my_handler(sender, **kwargs):
    send_mail('Subject', 'Your task was Overdue !', 'myemail@gmail.com', 'user_email', fail_silently=False)'

引发异常:

"NameError: name 'request isn't defined."

您正在尝试通过 request.user.email 访问请求而不请求访问,您可以在 index 查看时访问用户电子邮件,将电子邮件作为 **kwarg 传递并在 my_handler

def index(request):
    ...
    overdue_tasks = Todo.objects.filter(time__lte=timezone.now())
    if overdue_tasks:
        overdue.send_robust(sender=Todo, email=request.user.email)
    ...
    return render(request, 'todo/index.html', {'overdue_tasks' : overdue_tasks })

@receiver(overdue)
def my_handler(sender, **kwargs):
    email = kwargs.get('email')
    send_mail(foo)