如何在 gremlin 中创建不匹配 属性 值的顶点？

Question

My data model as below:
node:customer_entity

~id	telephone:String	Name	~label
c1	969874293	Tien	customer_entity
c1	987654145	Henry	customer_entity
c1	954682174	Bobby	customer_entity

node:membership_card

~id	Card_No_:String	created_at	~label
c1	969874293	22/01/2014	membership_card
c1	190019688	14/08/2009	membership_card
c1	954682174	08/12/2019	membership_card

I created phone_CDP node by using my query 

    g.V().hasLabel('customer_entity').
    as('phone_m').values('telephone').
    as('value_phone').
    addV('phone_CDP').
    property('id',select('value_phone')).
    addE('alias').to('phone_m') `

    g.V().hasLabel('membership_card').
    as('phone_l').values('Card_No_').as('value_phone').
    addV('phone_CDP').property('id',select('value_phone')).
    addE('alias').to('phone_l')

 my output:

id
969874293
987654145
954682174
969874293
190019688
954682174

 As you see i have two ids: 969874293 and 954682174 .So want to get one id value, how to do in my query? 

result i want :

id
969874293
987654145
954682174
190019688

Answer 1

您可以使用以下方法创建示例图表：

g = TinkerGraph.open().traversal()

g.addV('customer_entity').property('telephone', '969874293').
    addV('customer_entity').property('telephone', '987654145').
    addV('customer_entity').property('telephone', '954682174')

g.addV('membership_card').property('Card_No_', '969874293').
    addV('membership_card').property('Card_No_', '190019688').
    addV('membership_card').property('Card_No_', '954682174')

您可以添加 phone_CDP 个顶点：

g.V().hasLabel('customer_entity', 'membership_card').
    coalesce(values('telephone'),values('Card_No_')).as('phid').dedup().
    addV('phone_CDP').property('phoneId', select('phid')).elementMap()

==>[id:12,label:phone_CDP,phoneId:969874293]
==>[id:14,label:phone_CDP,phoneId:987654145]
==>[id:16,label:phone_CDP,phoneId:954682174]
==>[id:18,label:phone_CDP,phoneId:190019688]

您可以添加边：

g.V().hasLabel('customer_entity', 'membership_card').as('vfrom').
    coalesce(values('telephone'),values('Card_No_')).as('phid').
  V().has('phoneId').as('vto').values('phoneId').where(eq('phid')).
  select('vfrom').addE('alias').to('vto')

==>e[20][0-alias->12]
==>e[21][2-alias->14]
==>e[22][4-alias->16]
==>e[23][6-alias->12]
==>e[24][8-alias->18]
==>e[25][10-alias->16]