从 MySQL 中加入的 table 计算空值
Count null from joined table in MySQL
我需要从加入 MySQL 的 2 table 中计算 NULL。示例数据如下:
datefield FROM TABLE calendar (contain dates from start to end of this year)
-----------
TABLE value (data stored)
+------------+-------+
| date | keter |
+------------+-------+
| 2021-08-01 | 11 |
| 2021-08-04 | 0 |
| 2021-08-07 | 20 |
| 2021-08-08 | 15 |
| 2021-08-11 | 0 |
+------------+-------+
我正在使用以下查询来合并和显示来自日历和值 tables 的数据。
SELECT datefield,keter FROM calendar
LEFT JOIN kehadiran ON datefield=tgl AND id_kar IN ('110101')
WHERE datefield BETWEEN '2021-08-01' AND '2021-08-15' GROUP BY datefield;
result :
+------------+-------+
| datefield | keter |
+------------+-------+
| 2021-08-01 | 11 |
| 2021-08-02 | NULL |
| 2021-08-03 | NULL |
| 2021-08-04 | 0 |
| 2021-08-05 | NULL |
| 2021-08-06 | NULL |
| 2021-08-07 | 20 |
| 2021-08-08 | 15 |
| 2021-08-09 | NULL |
| 2021-08-10 | NULL |
| 2021-08-11 | 0 |
| 2021-08-12 | NULL |
| 2021-08-13 | NULL |
| 2021-08-14 | NULL |
| 2021-08-15 | NULL |
+------------+-------+
我根据这个问题()使用查询,没有得到我想要的结果。查询是这样的:
SELECT SUM(k.keter) FROM kehadiran k
LEFT OUTER JOIN calendar c ON c.datefield = k.keter AND id_kar IN ('110101')
WHERE datefield BETWEEN '2021-08-01' AND '2021-08-12' AND k.keter is NULL;
result:
+--------------+
| SUM(k.keter) |
+--------------+
| NULL |
+--------------+
the result i wanted :
+--------------+
| SUM(k.keter) |
+--------------+
| 10 |
+--------------+
我应该如何从上面提到的连接table中计算NULL?
您在查询中总结了 NULL。 NULL 的总和为 NULL。您应该将 SUM(k.keter)
替换为 COUNT(k.keter)
See 举个小例子
要计算 NULL
秒,您可以使用:
SUM(k.keter IS NULL)
或者:
COUNT(*) - COUNT(k.keter)
您在上次不正确的查询中交换了表。使用有效的查询并使用 COUNT(*)
和 WHERE right_table.any_notnull_column IS NULL
:
SELECT COUNT(*)
FROM calendar
LEFT JOIN kehadiran k ON datefield=tgl AND id_kar IN ('110101')
WHERE datefield BETWEEN '2021-08-01' AND '2021-08-15'
AND k.keter is NULL
我需要从加入 MySQL 的 2 table 中计算 NULL。示例数据如下:
datefield FROM TABLE calendar (contain dates from start to end of this year)
-----------
TABLE value (data stored)
+------------+-------+
| date | keter |
+------------+-------+
| 2021-08-01 | 11 |
| 2021-08-04 | 0 |
| 2021-08-07 | 20 |
| 2021-08-08 | 15 |
| 2021-08-11 | 0 |
+------------+-------+
我正在使用以下查询来合并和显示来自日历和值 tables 的数据。
SELECT datefield,keter FROM calendar
LEFT JOIN kehadiran ON datefield=tgl AND id_kar IN ('110101')
WHERE datefield BETWEEN '2021-08-01' AND '2021-08-15' GROUP BY datefield;
result :
+------------+-------+
| datefield | keter |
+------------+-------+
| 2021-08-01 | 11 |
| 2021-08-02 | NULL |
| 2021-08-03 | NULL |
| 2021-08-04 | 0 |
| 2021-08-05 | NULL |
| 2021-08-06 | NULL |
| 2021-08-07 | 20 |
| 2021-08-08 | 15 |
| 2021-08-09 | NULL |
| 2021-08-10 | NULL |
| 2021-08-11 | 0 |
| 2021-08-12 | NULL |
| 2021-08-13 | NULL |
| 2021-08-14 | NULL |
| 2021-08-15 | NULL |
+------------+-------+
我根据这个问题(
SELECT SUM(k.keter) FROM kehadiran k
LEFT OUTER JOIN calendar c ON c.datefield = k.keter AND id_kar IN ('110101')
WHERE datefield BETWEEN '2021-08-01' AND '2021-08-12' AND k.keter is NULL;
result:
+--------------+
| SUM(k.keter) |
+--------------+
| NULL |
+--------------+
the result i wanted :
+--------------+
| SUM(k.keter) |
+--------------+
| 10 |
+--------------+
我应该如何从上面提到的连接table中计算NULL?
您在查询中总结了 NULL。 NULL 的总和为 NULL。您应该将 SUM(k.keter)
替换为 COUNT(k.keter)
See 举个小例子
要计算 NULL
秒,您可以使用:
SUM(k.keter IS NULL)
或者:
COUNT(*) - COUNT(k.keter)
您在上次不正确的查询中交换了表。使用有效的查询并使用 COUNT(*)
和 WHERE right_table.any_notnull_column IS NULL
:
SELECT COUNT(*)
FROM calendar
LEFT JOIN kehadiran k ON datefield=tgl AND id_kar IN ('110101')
WHERE datefield BETWEEN '2021-08-01' AND '2021-08-15'
AND k.keter is NULL