从 PHP 随机播放并插入到新数据库 table 中获取输出

Question

我有下面的代码，可以随机播放 'users' table 中用户的输出。我希望能够按照洗牌对结果进行排序的顺序将洗牌后的结果发送到新的数据库 table。我希望每个排序结果在我的数据库中创建一个新行。

我不确定如何获取 PHP 随机播放的结果并将其发送。我添加了一个新的提交输入，所以当显示结果时，用户可以提交结果。洗牌过程中不能插入结果，必须在结果输出后插入。

如何从随机播放中获取结果并将其插入？我只是想看看如何获得当前结果。

$con = mysqli_connect("localhost", "", "", "db");
$query = mysqli_query($con, "SELECT * FROM users WHERE `group` = 3");

echo 'Normal results: <br>';
$array = array();
while ($row = mysqli_fetch_assoc($query)) {
    $array[] = $row;
    echo $row['firstname'] . ' ' . $row['lastname'] . '<br>';
}
?>
<form method="post">
    <input type="submit" value="Shuffle" name="shuffle">
</form>
<?php
if (isset($_POST['shuffle'])) {
    shuffle($array);
    echo 'Shuffled results: <br>';
    foreach ($array as $result) {
    $shuffle_firstname = $result['firstname'];
    $shuffle_lastname = $result['lastname'];
?>

<div id="shuffle_results">
        <?php echo $shuffle_firstname . ' ' . $shuffle_lastname . '<br>';?>
</div>
 <?php   }
}
 //What the new submit button will be like
 <form method="post">
        <input type="submit" value="Insert to db" name="insert">
    </form>

更新：添加了准备好的声明

<?php
$con = mysqli_connect("localhost", "root", "", "db");
$query = mysqli_query($con, "SELECT * FROM users WHERE `group` = 3");

echo 'Normal results: <br>';
$array = array();
while ($row = mysqli_fetch_assoc($query)) {
    $array[] = $row;
    echo $row['firstname'] . ' ' . $row['lastname'] . '<br>';
}
?>
<form method="POST">
    <input type="submit" value="Shuffle" name="shuffle">
</form>
<?php
if (isset($_POST['shuffle'])) {
    shuffle($array);
    echo 'Shuffled results: <br>';
    foreach ($array as $result) {
    $shuffle_id = $result['id'];
    $shuffle_firstname = $result['firstname'];
    $shuffle_lastname = $result['lastname'];
?>

<div id="shuffle_results">
     <?php echo '<ol>' . '<li>' . $shuffle_firstname . ' ' . $shuffle_lastname . '</li>' . '</ol>' . '<br>';?>
</div>
 <?php   }

}
($user->lastId);
    var_dump($user->insert_id);

if (isset($_POST['shuffle'])) {
    shuffle($array);
    ?>
    Shuffled results:<br>
    <form method="post">
    <?php
    foreach ($array as $result) {
        $shuffle_id = htmlentities($result['id']);
        $shuffle_firstname = htmlentities($result['firstname']);
        $shuffle_lastname = htmlentities($result['lastname']);
        $shuffle_username = htmlentities($result['username']);
        $shuffle_email = htmlentities($result['email']);

        ?>
        <div class="shuffle_results"><?php echo $shuffle_firstname . ' ' . $shuffle_lastname; ?></div>
        <input type="hidden" name="firstname[]" value="<?php echo $shuffle_firstname; ?>">
        <input type="hidden" name="lastname[]" value="<?php echo $shuffle_lastname; ?>">
        <?php
    }
    ?>
    <input type="submit" value="Insert to db" name="insert">
    </form>
    <?php
    $con = mysqli_connect("localhost", "root", "", "db");
    if (mysqli_connect_errno()) {
        printf("Connect failed: %s\n", mysqli_connect_error());
        exit();
    }
    $stmt2 = $con->prepare("INSERT INTO user_players (user_id, firstname, lastname, username, email) VALUES (?, ?, ?, ?, ?)");
    if ( false===$stmt2 ) {
         // Check Errors for prepare
        die('Add to user players prepare() failed: ' . htmlspecialchars($con->error));
    }
    $stmt2->bind_param('issss', $shuffle_id, $shuffle_firstname, $shuffle_lastname, $shuffle_username, $shuffle_email);
    if ( false===$stmt2 ) {
    // Check errors for binding parameters
        die('Add to user players bind_param() failed: ' . htmlspecialchars($stmt2->error));
    }
    $stmt2->execute();
    if ( false===$stmt2 ) {
        die('Add to user players execute() failed: ' . htmlspecialchars($stmt2->error));
    }
}

Answer 1

将打乱的名字放入表格的 <input type="hidden"> 个字段中。

if (isset($_POST['shuffle'])) {
    shuffle($array);
    ?>
    Shuffled results:<br>
    <form method="post">
    foreach ($array as $result) {
        $shuffle_firstname = htmlentities($result['firstname']);
        $shuffle_lastname = htmlentities($result['lastname']);
        $shuffle_id = htmlentities($result['id']);
        $shuffle_username = htmlentities($result['username']);
        $shuffle_email = htmlentities($result['email']);

        ?>
        <div class="shuffle_results"><?php echo $shuffle_firstname . ' ' . $shuffle_lastname; ?></div>
        <input type="hidden" name="firstname[]" value="<?php echo $shuffle_firstname; ?>">
        <input type="hidden" name="lastname[]" value="<?php echo $shuffle_lastname; ?>">
        <input type="hidden" name="id[]" value="<?php echo $shuffle_id; ?>">
        <input type="hidden" name="username[]" value="<?php echo $shuffle_username; ?>">
        <input type="hidden" name="email[]" value="<?php echo $shuffle_email; ?>">
        <?php
    }
    <input type="submit" value="Insert to db" name="insert">
    </form>
}

提交此表单时，$_POST['firstname']和$_POST['lastname']将是数组，因此您可以遍历它们并将它们插入到新的table。

if (isset($_POST['insert'])) {
    $con = mysqli_connect("localhost", "root", "", "db");
    if (mysqli_connect_errno()) {
        printf("Connect failed: %s\n", mysqli_connect_error());
        exit();
    }
    $stmt2 = $con->prepare("INSERT INTO user_players (user_id, firstname, lastname, username, email) VALUES (?, ?, ?, ?, ?)");
    if ( false===$stmt2 ) {
         // Check Errors for prepare
        die('Add to user players prepare() failed: ' . htmlspecialchars($con->error));
    }
    $stmt2->bind_param('issss', $shuffle_id, $shuffle_firstname, $shuffle_lastname, $shuffle_username, $shuffle_email);

    foreach ($_POST['id'] as $i => $shuffle_id) {
        $shuffle_firstname = $_POST['firstname'][$i];
        $shuffle_lastname = $_POST['lastname'][$i];
        $shuffle_username = $_POST['username'][$i];
        $shuffle_email = $_POST['email'][$i];
        $stmt2->execute() or
            die('Add to user players execute() failed: ' . htmlspecialchars($stmt2->error));
    }
}

请注意，对于 shuffle_results DIV，您应该使用 class 而不是 ID，因为您要为结果中的每一行添加一个。 ID 必须是唯一的。

您也可以只将 $result['id'] 放在 insert 形式中，而无需所有其他隐藏输入。然后处理它的脚本可以从 users table 中获取其他字段并将它们插入 user_players.

$stmt2 = $con->prepare("INSERT INTO user_players (user_id, firstname, lastname, username, email)
                        SELECT user_id, firstname, lastname, username, email
                        FROM users 
                        WHERE id = ?");
$stmt2->bind_param("i", $shuffle_id);
foreach ($_POST['id'] as $shuffle_id) {
    $stmt2->execute() or die('Add to user players execute() failed: ' . htmlspecialchars($stmt2->error));
}

从 PHP 随机播放并插入到新数据库 table 中获取输出

Getting output from a PHP shuffle and INSERT into new database table

php

mysql

forms

insert