比较列表中的所有元素

Question

如何计算列表中元组的出现次数，而不考虑元组项的顺序？例如;

the_list = [
    (one, two, three),
    (two, three, four),
    (one, three, two),
    (one, two, three),
    (four, two, one),
]

在上面的列表中，我希望 (one, two, three) 和 (one, three, two) 相等，并算作相同的东西。

Answer 1

您可以在开始计数之前使用计数器对它们进行排序

thelist = [(1,2,3), (2,3,4), (1,3,2), (1,2,3), (4,2,1)]
from collections import Counter
Counter(tuple(sorted(x)) for x in thelist)

Counter({(1, 2, 3): 3, (2, 3, 4): 1, (1, 2, 4): 1})

Compare all elements of list between themselves