C# 屏幕捕获和流式传输

Question

我只是想在 C# 上使用 TCP 协议流式捕获屏幕。

private Bitmap bmpScreenshot;

private byte[] screenToByteArray()
{
    byte[] result;

    try
    {
        if (bmpScreenshot != null)
            bmpScreenshot.Dispose();

        bmpScreenshot = new Bitmap(SystemInformation.VirtualScreen.Width,
                       SystemInformation.VirtualScreen.Height,
                       PixelFormat.Format32bppArgb);

        using (var gfxScreenshot = Graphics.FromImage(bmpScreenshot))
        {
            gfxScreenshot.CopyFromScreen(SystemInformation.VirtualScreen.X,
                                        SystemInformation.VirtualScreen.Y,
                                        0,
                                        0,
                                        SystemInformation.VirtualScreen.Size,
                                        CopyPixelOperation.SourceCopy);

            result = ImageToByte(bmpScreenshot);
        }
    }
    catch (Exception ex)
    {
        Console.WriteLine("[ERROR]screenToByteArray Error..{0}", ex.Message);
        result = null;
    }
    return result;
}


private byte[] ImageToByte(Image iImage)
{
    if (mMemoryStream != null)
        mMemoryStream.Dispose();

    mMemoryStream = new MemoryStream();
    iImage.Save(mMemoryStream, ImageFormat.Png);

    if (iImage != null)
        iImage.Dispose();

    return mMemoryStream.ToArray();
}

我使用该代码部分并发送 screenToByteArray() 但我遇到了问题。如果我的屏幕没有很多这样的图像 enter image description here, Listener can see correct display, but When my screen has complicated image(s) like that enter image description here , Listener sees distorted display like that enter image description here 。当我的屏幕有任何复杂的图像时，听众无法看到整个显示。我怎样才能做到这一点。感谢您的帮助。

编辑我在下面分享我的 tcp 代码

Socket socket = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp);
socket.Connect(new IPEndPoint(IPAddress.Parse("192.168.1.109"), 8500));

while(true)
{
    try
    {
            byte[] sendData = screenToByteArray();
            socket.Send(sendData, sendData.Length, SocketFlags.None);

            sendData = null;
    }
    catch (Exception ex)
    {
        Console.WriteLine("[ERROR]sendScreen Error..{0}", ex.Message);
        socket.Dispose();
        break;
    }
 }

Answer 1

我做到了。流式传输图片格式已更改。

        private byte[] ImageToByte(Image iImage)
        {
            if (mMemoryStream != null)
                mMemoryStream.Dispose();

            mMemoryStream = new MemoryStream();
            iImage.Save(mMemoryStream, ImageFormat.Jpeg);

            if (iImage != null)
                iImage.Dispose();

            return mMemoryStream.ToArray();
        }

C# 屏幕捕获和流式传输

C# Screen Capture and Streaming

.net

c#

sockets

screenshot

screen-capture