Flask 路由未在 Python 上调用 Yelp API

Question

所以我在我的索引页面上创建了这条路由，它从 HTML 表单中获取 POST 并在 API 调用中输入变量。我认为 for 循环的初始问题是遍历字典，但根据 yelp 上的 API 用法，似乎 API 甚至没有被调用。有谁知道为什么这条路线不能正常工作？谢谢

@app.route("/",methods=["POST", "GET"])
def zipsub():
    global gym_df
    if request.method == "POST" and 'zipsearch' in request.form:
        zip_code = request.form.get['zipsearch']
        #Client ID
        clientid = 'client_id'
        #define api key, endpoint and header for request to yelp API
        api_key = 'api_key'
        end_point = 'https://api.yelp.com/v3/businesses/search'
        resp_header = {'Authorization': 'bearer {}'.format(api_key)}
        
        #define parameters
        parameters = {'term':'gym',
                        'limit':5,
                        'radius':3200,
                        'location':'{}'.format(zip_code),
                        }
        #make api call
        response = reqs.get(url=end_point, params=parameters, headers=resp_header)

        #Change json into dict then to pandas dataframe
        gym_dict = response.json()

        for valg in gym_dict['businesses']:
            if valg in gym_dict['businesses']:
                #only display street address
                valg['location']['display_address'] = valg['location']['display_address'][0]
                data = valg['image_url'],valg['name'],valg['location']['display_address'],valg['rating'],valg['phone']
                datalist = list(data)
                seriesly = pd.Series(datalist, index = gym_df.columns)
                gym_df = gym_df.append(seriesly, ignore_index=True)
                #ORDER DATAFRAME BY RATING
                gym_df = gym_df.sort_values(by=['Rating'], ascending=False)
                #gym_df.to_html(headers='True', table_id='my_table')
                gym_df.to_sql("gym_df", engine, if_exists='append')

    return render_template('table.html', tables=gym_df.to_html(table_id='my_table'))

Answer 1

改变了这个：

def zipsub():
    global gym_df
    if request.method == "POST":
        zip_code = request.form.get('zipsearch')
        #Client ID

和

return render_template('table.html', column_names=gym_df.columns.values, row_data=list(gym_df.values.tolist()), zip=zip)

此修复让我可以正确地调用和解压缩 API 结果。

Flask 路由未在 Python 上调用 Yelp API

Flask route is not calling Yelp API on Python

python

flask

flask-sqlalchemy