在 Postgresql 中批量插入

Question

你好，我有这个简单的插入语句

insert into location_access (employee,location,permissionid)
values
(empID,8241,4),
(empID,8260,4),
(empID,8269,4),
(empID,8261,4),
(empID,8170,4),
(empID,7908,4),
(empID,8008,4),
(empID,8026,4),
(empID,8029,4),
(empID,8242,4),
(empID,8270,4),
(empID,8278,4),
(empID,8279,4),
(empID,8281,4),
(empID,8284,4),
(empID,8288,4),
(empID,8171,4),
(empID,7909,4),
(empID,8156,4),
(empID,7258,4),
(empID,8027,4)

对于 empiD，我还有一个包含 190 多个 employeeID 的列表所以对这些值进行硬编码会很痛苦有没有更好的方法来做到这一点可能是一个“循环” 循环所有员工 ID 并将它们添加到每个位置？

示例员工 ID

Answer 1

使用For循环，可以插入多条记录

DO
$do$
DECLARE
   a integer[] := array[41743,41746,41753,43554,43557,43561,43582,43584 ];
   i integer;                   
BEGIN
   FOR i IN 1 .. array_upper(a, 1)
   LOOP
      RAISE NOTICE '%', a[i];      -- single quotes
      insert into location_access (employee,location,permissionid)
values
(a[i],8241,4);
   END LOOP;
END
$do$;

这是演示https://extendsclass.com/postgresql/ecb3b7c

Answer 2

您可以交叉加入员工 ID 列表：

insert into location_access (employee,location,permissionid)
select source.employee, source.location, source.permissionid
from (
 values
   (41743),(41746),(41753),(43554),(43557),(43561),
   (43563),(43568),(43569),(43570),(43572),(43573),
   (43574),(43576),(43577),(43579),(43582),(43584)
) as emp(empid) 
  cross join lateral (
    values 
      (emp.empid,8241,4),
      (emp.empid,8260,4),
      (emp.empid,8269,4),
      (emp.empid,8261,4),
      (emp.empid,8170,4),
      (emp.empid,7908,4),
      (emp.empid,8008,4),
      (emp.empid,8026,4),
      (emp.empid,8029,4),
      (emp.empid,8242,4),
      (emp.empid,8270,4),
      (emp.empid,8278,4),
      (emp.empid,8279,4),
      (emp.empid,8281,4),
      (emp.empid,8284,4),
      (emp.empid,8288,4),
      (emp.empid,8171,4),
      (emp.empid,7909,4),
      (emp.empid,8156,4),
      (emp.empid,7258,4),
      (emp.empid,8027,4)
   ) as source(employee,location,permissionid)

在 Postgresql 中批量插入

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