SQL:查找在一周的特定日期雇用的所有员工

SQL: Finding all employees hired on a specific day of the week

我很难找到在一周中的某一天(星期一、星期二等)雇用率最高的所有员工。

例如:如果星期一是雇用人数最多的一天,我想显示一周中这一天雇用的所有员工。

我发现哪些日子的招聘人数最多:

SELECT COUNT(*), TO_CHAR(HIRE_DATE,'DAY') DAY
FROM EMPLOYEES
GROUP BY TO_CHAR(HIRE_DATE,'DAY')
HAVING COUNT (*)=(SELECT MAX(COUNT(*))FROM EMPLOYEES GROUP BY TO_CHAR(HIRE_DATE,'DAY'));

但我无法显示当天雇用的所有员工。预先感谢您的宝贵时间。

我不懂 Oracle 语法,但在该查询中加入了 EMPLOYEES。类似于:

SELECT  e.*
FROM EMPLOYEES e
INNER JOIN
    (SELECT <employee id>, TO_CHAR(HIRE_DATE,'DAY') DAY
    FROM EMPLOYEES
    GROUP BY TO_CHAR(HIRE_DATE,'DAY')
    HAVING COUNT (*)=(SELECT MAX(COUNT(*))FROM EMPLOYEES GROUP BY TO_CHAR(HIRE_DATE,'DAY'))) AS empdays
    ON TO_CHAR(e.HIRE_DATE, 'DAY') = empdays.DAY;

怎么样:

select * from employees
where to_char(HIRE_DATE,'DAY') in

SELECT TO_CHAR(HIRE_DATE,'DAY') DAY
FROM EMPLOYEES
GROUP BY TO_CHAR(HIRE_DATE,'DAY')
HAVING COUNT (*)=(SELECT MAX(COUNT(*))FROM EMPLOYEES GROUP BY TO_CHAR(HIRE_DATE,'DAY'));