管理面板中一对一用户模型的错误自定义字段

Question

我创建了自定义 Subscriber 一对一模型来扩展现有的 Django 用户模型。 （我知道用AbstractUser更好，但我只是想尝试一下学习）

我可以通过 shell 成功创建新用户，并且我可以编辑（在管理面板中）用户在创建后 具有的自定义字段 。但是，由于错误，我无法在不使用 shell 的情况下在管理面板中创建新用户。

我想 admin.py 有问题吗？

错误：

IntegrityError at /admin/auth/user/add/

UNIQUE constraint failed: app_subscriber.user_id

models.py

from django.db import models
from django.contrib.auth.models import User
from django.db.models.signals import post_save
from django.dispatch import receiver


class Subscriber(models.Model):
    user = models.OneToOneField(User, on_delete=models.CASCADE)
    location = models.CharField(max_length=30, blank=True)


@receiver(post_save, sender=User)
def create_user_subscriber(sender, instance, created, **kwargs):
    if created:
        Subscriber.objects.create(user=instance)


@receiver(post_save, sender=User)
def save_user_subscriber(sender, instance, **kwargs):
    instance.subscriber.save()

admin.py

from django.contrib import admin
from django.contrib.auth.admin import UserAdmin as BaseUserAdmin
from django.contrib.auth.models import User

from . import models


# Define an inline admin descriptor for Subscriber model
# which acts a bit like a singleton
class SubscriberInline(admin.StackedInline):
    model = models.Subscriber
    can_delete = False
    verbose_name_plural = 'subscribers'

# Define a new User admin
class UserAdmin(BaseUserAdmin):
    inlines = (SubscriberInline,)

# Re-register UserAdmin
admin.site.unregister(User)
admin.site.register(User, UserAdmin)

Answer 1

不适合创建两个相同的信号（post_save 用户），只创建一个并在其上做所有事情

@receiver(post_save, sender=User)
def create_user_subscriber(sender, instance, created, **kwargs):
    if created:
        Subscriber.objects.create(user=instance)


@receiver(post_save, sender=User)
def save_user_subscriber(sender, instance, **kwargs):
    instance.subscriber.save()

你的错误提示你不能为同一个用户创建 2 个订阅者（UNIQUE 约束）

这解决了你的问题

@receiver(post_save, sender=User)
def create_user_subscriber(sender, instance, created, **kwargs):
    # you check if instance are 'subscriber' related name create by OneToOneField , if not create Subcriber model
    if created and not hasattr(instance, 'subscriber'):
        Subscriber.objects.create(user=instance)

管理面板中一对一用户模型的错误自定义字段

Erroneous custom field of the one-to-one User model in the Admin Panel

django

django-admin

django-users