在 SQL 服务器中解析 XML （使用数组）

Question

我正在尝试解析 SQL 服务器中的一些 XML，我已经开发了一些代码来执行此操作，但是返回的数据项之一以数组的形式出现？

SQL 到目前为止，示例 XML...

DECLARE @XML XML
SET @XML = '<?xml version="1.0" encoding="UTF-8"?>
<feedback-items>
<feedback-item id="1001">
<message>The message</message>
<sentiment-score>3</sentiment-score>
<channel>SMS</channel>
<structured-fields>
<structured-field>
<name>loyalty_card_number</name>
<value>123456</value>
</structured-field>
<structured-field>
<name>given_score</name>
<value>4</value>
</structured-field>
</structured-fields>
<categories>
<category>People</category>
<category>Process</category>
<category>Product</category>
<category>Place</category>
</categories>
<insights>
<insight>
<category>People</category>
<sentiment-score>1</sentiment-score>
</insight>
</insights>
<notes>
<note>
<id>1</id>
<username>Bob</username>
<created>2012-12-11 09:00:00</created>
<content>The customer was happy</content>
</note>
</notes>
</feedback-item>
<feedback-item id="1002">
<message>The message</message>
<sentiment-score>3</sentiment-score>
<channel>SMS</channel>
<structured-fields>
<structured-field>
<name>loyalty_card_number</name>
<value>123456</value>
</structured-field>
<structured-field>
<name>given_score</name>
<value>6</value>
</structured-field>
</structured-fields>
<categories>
<category>People</category>
<category>Process</category>
<category>Product</category>
<category>Place</category>
</categories>
<insights>
<insight>
<category>People</category>
<sentiment-score>1</sentiment-score>
</insight>
</insights>
<notes>
<note>
<id>1</id>
<username>Mike</username>
<created>2012-12-12 09:00:00</created>
<content>The customer was happy</content>
</note>
</notes>
</feedback-item>
</feedback-items>
'

SELECT 
    xmlData.A.value('@id','INT') AS [FeedbackItem]
    --fields.A.value('./Name/text())[1]','Varchar(50)') AS [Name]
    --xmlData.A.value('(./structured-fields/structured-field/Name/text())[1]','Varchar(50)') AS [Name]
FROM @XML.nodes('feedback-items/feedback-item') xmlData(A)
        --CROSS APPLY xmlData.A.nodes('/structured-fields/structured-field') AS fields(A)

期望的输出...

Feedback Item	Message	Sentiment Score	Channel	Loyalty Card Number	Given Score	Username	Created	Content
1001	The message	3	SMS	123456	6	Bob	2012-12-11	The Customer was happy
1002	The message	3	SMS	123456	4	Mike	2012-12-12	The Customer was happy

Answer 1

请尝试以下解决方案。

您的 XPath 表达式有问题。

SQL

DECLARE @xml XML =
N'<feedback-items>
    <feedback-item id="1001">
        <message>The message</message>
        <sentiment-score>3</sentiment-score>
        <channel>SMS</channel>
        <structured-fields>
            <structured-field>
                <name>loyalty_card_number</name>
                <value>123456</value>
            </structured-field>
            <structured-field>
                <name>given_score</name>
                <value>4</value>
            </structured-field>
        </structured-fields>
        <categories>
            <category>People</category>
            <category>Process</category>
            <category>Product</category>
            <category>Place</category>
        </categories>
        <insights>
            <insight>
                <category>People</category>
                <sentiment-score>1</sentiment-score>
            </insight>
        </insights>
        <notes>
            <note>
                <id>1</id>
                <username>Bob</username>
                <created>2012-12-11 09:00:00</created>
                <content>The customer was happy</content>
            </note>
        </notes>
    </feedback-item>
    <feedback-item id="1002">
        <message>The message</message>
        <sentiment-score>3</sentiment-score>
        <channel>SMS</channel>
        <structured-fields>
            <structured-field>
                <name>loyalty_card_number</name>
                <value>123456</value>
            </structured-field>
            <structured-field>
                <name>given_score</name>
                <value>6</value>
            </structured-field>
        </structured-fields>
        <categories>
            <category>People</category>
            <category>Process</category>
            <category>Product</category>
            <category>Place</category>
        </categories>
        <insights>
            <insight>
                <category>People</category>
                <sentiment-score>1</sentiment-score>
            </insight>
        </insights>
        <notes>
            <note>
                <id>1</id>
                <username>Mike</username>
                <created>2012-12-12 09:00:00</created>
                <content>The customer was happy</content>
            </note>
        </notes>
    </feedback-item>
</feedback-items>
';

SELECT a.value('@id','INT') AS [FeedbackItem]
    , a.value('(message/text())[1]','Varchar(50)') AS [Message]
    , a.value('(sentiment-score/text())[1]','Varchar(50)') AS [SentimentScore]
    , a.value('(channel/text())[1]','Varchar(50)') AS [channel]
    , a.value('(structured-fields/structured-field[name="loyalty_card_number"]/value/text())[1]','Varchar(50)') AS [loyalty_card_number]
    , a.value('(structured-fields/structured-field[name="given_score"]/value/text())[1]','Varchar(50)') AS [GivenScore]
    , b.value('(username/text())[1]','Varchar(50)') AS [Username]
    , b.value('(created/text())[1]','DATE') AS [created]
    , b.value('(content/text())[1]','VARCHAR(100)') AS [content]
FROM @XML.nodes('/feedback-items/feedback-item') t1(a)
    CROSS APPLY t1.a.nodes('notes/note') AS t2(b);

输出

+--------------+-------------+----------------+---------+---------------------+------------+----------+------------+------------------------+
| FeedbackItem |   Message   | SentimentScore | channel | loyalty_card_number | GivenScore | Username |  created   |        content         |
+--------------+-------------+----------------+---------+---------------------+------------+----------+------------+------------------------+
|         1001 | The message |              3 | SMS     |              123456 |          4 | Bob      | 2012-12-11 | The customer was happy |
|         1002 | The message |              3 | SMS     |              123456 |          6 | Mike     | 2012-12-12 | The customer was happy |
+--------------+-------------+----------------+---------+---------------------+------------+----------+------------+------------------------+

Answer 2

您可以使用以下代码

SELECT
  [Feedback Item] = fb.value('@id','int'),
  Message = fb.value('(message/text())[1]','nvarchar(200)'),
  [Sentiment Score] = fb.value('(sentiment-score/text())[1]','int'),
  Channel = fb.value('(channel/text())[1]','nvarchar(200)'),
  [Loyalty Card Number] = fb.value('(structured-fields/structured-field[name[text()="loyalty_card_number"]]/value/text())[1]','nvarchar(200)'),
  [Given Score] = fb.value('(structured-fields/structured-field[name[text()="given_score"]]/value/text())[1]','nvarchar(200)'),
  Username = fb.value('(notes/note/username/text())[1]','nvarchar(200)'),
  Created = fb.value('(notes/note/created/text())[1]','datetime'),
  Content = fb.value('(notes/note/content/text())[1]','nvarchar(200)')
FROM @xml.nodes('feedback-items/feedback-item') x(fb)

db<>fiddle

进一步说明：

XML 被截断了，我向其中添加了一些以获得所需的结果。我假设你有更多。
请注意如何在 name/text() 上过滤 structured-field，然后检索 value/text(0
notes/note 看起来它可能包含多个项目，您可能需要将其与另一个 .nodes

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