Oracle sql 查询
Oracle sql query
我正在处理 tables，它们（出于此处显示的目的）如下所示：
一个
A_ID | Clob_Col
1 | value
2 | value
3 | null
4 | value
5 | null
6 | value
7 | value
8 | null
9 | value
10 | value
乙
B_ID |A_ID | C_ID
10 | 1 | 20
11 | 2 | 20
12 | 6 | 21
13 | 7 | 22
14 | 8 | 22
15 | 9 | 23
C
C_ID
20
21
22
23
24
25
（所有 table 都有更多列）
我希望编写一个查询，该查询将从所有三个 table 中获取 return 值，但排除某些值与 Table C（NOT IN）中的值匹配的记录。
我的问题是 return 来自 Table A 的值 不 link 到 Table B 当使用 NOT IN 子句时Table C.
示例：
SELECT a.A_ID, a.Clob_Col, b.B_ID, c.C_ID
from A a
LEFT JOIN B b on a.A_ID=b.A_ID
LEFT JOIN C c on b.C_ID=c.C_ID
WHERE a.AID >= 2
AND a.AID <= 7
AND c.C_ID NOT IN (22, 23, 24)
最后一行 - c.C_ID NOT IN (22, 23, 24) - 将在 B table 中留下以下记录：b_BID = 10,11 或 12
依次将这些link记录在TableA中：a.ID=1,2和6.
第一个子句 - a.AID >= 2 AND a.AID <= 7 - 进一步将我们的最终结果限制为 a.ID = 2 和 6。
最终结果将如下所示：
A_ID |Clob_Col |B_ID |C_ID
2 |value |11 |20
6 |value |12 |21
但是我也想return A table记录而不是link到Table B - a.ID 3、4 和 5
所以我希望我的结果是
A_ID |Clob_Col |B_ID |C_ID
2 |value |11 |20
3 |null |null |null
4 |value |null |null
5 |null |null |null
6 |value |12 |21
注意：我包含 Clob 值的原因是有人建议选择所有记录，然后对 c.C_ID IN (22, 23, 24).
的记录执行减法运算
这似乎是合理的，但是 Oracle 不允许涉及 Clob 列的 MINUS 操作。
我想你忘了使用 "on" 子句进行连接。你可以试试这个：
SELECT a.A_ID, a.Clob_Col, b.B_ID, c.C_ID
from A a
LEFT JOIN B b on a.A_ID=b.A_ID
LEFT JOIN C c on b.C_ID=c.C_ID
WHERE a.A_ID between 2 and 7
AND c.C_ID NOT IN (22, 23, 24)
希望它能奏效。
包括你加入的内容，你也可以使用 BETWEEN 作为第一个 WHERE 子句。
此外，根据您的数据，我会使用 INNER JOINS 而不是 LEFT。
SELECT a.A_ID, a.Clob_Col, b.B_ID, c.C_ID
FROM A a
INNER JOIN B b ON a.A_ID = b.B_ID
INNER JOIN C c ON b.C_ID = c.C_ID
WHERE a.AID BETWEEN 2 AND 7
AND c.C_ID NOT IN (22, 23, 24)
我认为这可以满足您的需求：
with a as (select 1 a_id, 'val1' clob_col from dual union all
select 2 a_id, 'val2' clob_col from dual union all
select 3 a_id, null clob_col from dual union all
select 4 a_id, 'val4' clob_col from dual union all
select 5 a_id, null clob_col from dual union all
select 6 a_id, 'val6' clob_col from dual union all
select 7 a_id, 'val7' clob_col from dual union all
select 8 a_id, null clob_col from dual union all
select 9 a_id, 'val9' clob_col from dual union all
select 10 a_id, 'val10' clob_col from dual),
b as (select 10 b_id, 1 a_id, 20 c_id from dual union all
select 11 b_id, 2 a_id, 20 c_id from dual union all
select 12 b_id, 6 a_id, 21 c_id from dual union all
select 13 b_id, 7 a_id, 22 c_id from dual union all
select 14 b_id, 8 a_id, 22 c_id from dual union all
select 15 b_id, 9 a_id, 23 c_id from dual),
c as (select 20 c_id from dual union all
select 21 c_id from dual union all
select 22 c_id from dual union all
select 23 c_id from dual union all
select 24 c_id from dual union all
select 25 c_id from dual)
select a.a_id, a.clob_col, b.b_id, c.c_id
from a
left outer join b on (a.a_id = b.a_id)
left outer join c on (b.c_id = c.c_id)
where a.a_id between 2 and 7
and (c.c_id not in (22, 23, 24) or c.c_id is null)
order by a.a_id;
A_ID CLOB_COL B_ID C_ID
---------- -------- ---------- ----------
2 val2 11 20
3
4 val4
5
6 val6 12 21
and if c_id is 27 for a_id = 6 in the b table:
A_ID CLOB_COL B_ID C_ID
---------- -------- ---------- ----------
2 val2 11 20
3
4 val4
5
6 val6 12
您必须考虑到 c_id 可能为空，并且不在被排除的值集中这一事实。
ETA：感谢 Ponder Stibbons 在评论中的建议，如果您不希望在 a.a_id = b.a_id 匹配但没有匹配 [= =22=] = c.c_id，然后将 or c.c_id is null 更改为 or b.c_id is null 删除该行：
with a as (select 1 a_id, 'val1' clob_col from dual union all
select 2 a_id, 'val2' clob_col from dual union all
select 3 a_id, null clob_col from dual union all
select 4 a_id, 'val4' clob_col from dual union all
select 5 a_id, null clob_col from dual union all
select 6 a_id, 'val6' clob_col from dual union all
select 7 a_id, 'val7' clob_col from dual union all
select 8 a_id, null clob_col from dual union all
select 9 a_id, 'val9' clob_col from dual union all
select 10 a_id, 'val10' clob_col from dual),
b as (select 10 b_id, 1 a_id, 20 c_id from dual union all
select 11 b_id, 2 a_id, 20 c_id from dual union all
select 12 b_id, 6 a_id, 27 c_id from dual union all
select 13 b_id, 7 a_id, 22 c_id from dual union all
select 14 b_id, 8 a_id, 22 c_id from dual union all
select 15 b_id, 9 a_id, 23 c_id from dual),
c as (select 20 c_id from dual union all
select 21 c_id from dual union all
select 22 c_id from dual union all
select 23 c_id from dual union all
select 24 c_id from dual union all
select 25 c_id from dual)
select a.a_id, a.clob_col, b.b_id, c.c_id
from a
left outer join b on (a.a_id = b.a_id)
left outer join c on (b.c_id = c.c_id)
where a.a_id between 2 and 7
and (c.c_id not in (22, 23, 24) or b.c_id is null)
order by a.a_id;
我正在处理 tables，它们（出于此处显示的目的）如下所示：
一个
A_ID | Clob_Col
1 | value
2 | value
3 | null
4 | value
5 | null
6 | value
7 | value
8 | null
9 | value
10 | value
乙
B_ID |A_ID | C_ID
10 | 1 | 20
11 | 2 | 20
12 | 6 | 21
13 | 7 | 22
14 | 8 | 22
15 | 9 | 23
C
C_ID
20
21
22
23
24
25
（所有 table 都有更多列）
我希望编写一个查询，该查询将从所有三个 table 中获取 return 值，但排除某些值与 Table C（NOT IN）中的值匹配的记录。 我的问题是 return 来自 Table A 的值 不 link 到 Table B 当使用 NOT IN 子句时Table C.
示例：
SELECT a.A_ID, a.Clob_Col, b.B_ID, c.C_ID
from A a
LEFT JOIN B b on a.A_ID=b.A_ID
LEFT JOIN C c on b.C_ID=c.C_ID
WHERE a.AID >= 2
AND a.AID <= 7
AND c.C_ID NOT IN (22, 23, 24)
最后一行 - c.C_ID NOT IN (22, 23, 24) - 将在 B table 中留下以下记录：b_BID = 10,11 或 12
依次将这些link记录在TableA中：a.ID=1,2和6.
第一个子句 - a.AID >= 2 AND a.AID <= 7 - 进一步将我们的最终结果限制为 a.ID = 2 和 6。
最终结果将如下所示：
A_ID |Clob_Col |B_ID |C_ID
2 |value |11 |20
6 |value |12 |21
但是我也想return A table记录而不是link到Table B - a.ID 3、4 和 5 所以我希望我的结果是
A_ID |Clob_Col |B_ID |C_ID
2 |value |11 |20
3 |null |null |null
4 |value |null |null
5 |null |null |null
6 |value |12 |21
注意：我包含 Clob 值的原因是有人建议选择所有记录，然后对 c.C_ID IN (22, 23, 24).
这似乎是合理的，但是 Oracle 不允许涉及 Clob 列的 MINUS 操作。
我想你忘了使用 "on" 子句进行连接。你可以试试这个：
SELECT a.A_ID, a.Clob_Col, b.B_ID, c.C_ID
from A a
LEFT JOIN B b on a.A_ID=b.A_ID
LEFT JOIN C c on b.C_ID=c.C_ID
WHERE a.A_ID between 2 and 7
AND c.C_ID NOT IN (22, 23, 24)
希望它能奏效。
包括你加入的内容，你也可以使用 BETWEEN 作为第一个 WHERE 子句。
此外，根据您的数据，我会使用 INNER JOINS 而不是 LEFT。
SELECT a.A_ID, a.Clob_Col, b.B_ID, c.C_ID
FROM A a
INNER JOIN B b ON a.A_ID = b.B_ID
INNER JOIN C c ON b.C_ID = c.C_ID
WHERE a.AID BETWEEN 2 AND 7
AND c.C_ID NOT IN (22, 23, 24)
我认为这可以满足您的需求：
with a as (select 1 a_id, 'val1' clob_col from dual union all
select 2 a_id, 'val2' clob_col from dual union all
select 3 a_id, null clob_col from dual union all
select 4 a_id, 'val4' clob_col from dual union all
select 5 a_id, null clob_col from dual union all
select 6 a_id, 'val6' clob_col from dual union all
select 7 a_id, 'val7' clob_col from dual union all
select 8 a_id, null clob_col from dual union all
select 9 a_id, 'val9' clob_col from dual union all
select 10 a_id, 'val10' clob_col from dual),
b as (select 10 b_id, 1 a_id, 20 c_id from dual union all
select 11 b_id, 2 a_id, 20 c_id from dual union all
select 12 b_id, 6 a_id, 21 c_id from dual union all
select 13 b_id, 7 a_id, 22 c_id from dual union all
select 14 b_id, 8 a_id, 22 c_id from dual union all
select 15 b_id, 9 a_id, 23 c_id from dual),
c as (select 20 c_id from dual union all
select 21 c_id from dual union all
select 22 c_id from dual union all
select 23 c_id from dual union all
select 24 c_id from dual union all
select 25 c_id from dual)
select a.a_id, a.clob_col, b.b_id, c.c_id
from a
left outer join b on (a.a_id = b.a_id)
left outer join c on (b.c_id = c.c_id)
where a.a_id between 2 and 7
and (c.c_id not in (22, 23, 24) or c.c_id is null)
order by a.a_id;
A_ID CLOB_COL B_ID C_ID
---------- -------- ---------- ----------
2 val2 11 20
3
4 val4
5
6 val6 12 21
and if c_id is 27 for a_id = 6 in the b table:
A_ID CLOB_COL B_ID C_ID
---------- -------- ---------- ----------
2 val2 11 20
3
4 val4
5
6 val6 12
您必须考虑到 c_id 可能为空，并且不在被排除的值集中这一事实。
ETA：感谢 Ponder Stibbons 在评论中的建议，如果您不希望在 a.a_id = b.a_id 匹配但没有匹配 [= =22=] = c.c_id，然后将 or c.c_id is null 更改为 or b.c_id is null 删除该行：
with a as (select 1 a_id, 'val1' clob_col from dual union all
select 2 a_id, 'val2' clob_col from dual union all
select 3 a_id, null clob_col from dual union all
select 4 a_id, 'val4' clob_col from dual union all
select 5 a_id, null clob_col from dual union all
select 6 a_id, 'val6' clob_col from dual union all
select 7 a_id, 'val7' clob_col from dual union all
select 8 a_id, null clob_col from dual union all
select 9 a_id, 'val9' clob_col from dual union all
select 10 a_id, 'val10' clob_col from dual),
b as (select 10 b_id, 1 a_id, 20 c_id from dual union all
select 11 b_id, 2 a_id, 20 c_id from dual union all
select 12 b_id, 6 a_id, 27 c_id from dual union all
select 13 b_id, 7 a_id, 22 c_id from dual union all
select 14 b_id, 8 a_id, 22 c_id from dual union all
select 15 b_id, 9 a_id, 23 c_id from dual),
c as (select 20 c_id from dual union all
select 21 c_id from dual union all
select 22 c_id from dual union all
select 23 c_id from dual union all
select 24 c_id from dual union all
select 25 c_id from dual)
select a.a_id, a.clob_col, b.b_id, c.c_id
from a
left outer join b on (a.a_id = b.a_id)
left outer join c on (b.c_id = c.c_id)
where a.a_id between 2 and 7
and (c.c_id not in (22, 23, 24) or b.c_id is null)
order by a.a_id;