无法推断通用参数 'T' - Swift 5.5

Question

我正在尝试让用户登录，但出现以下错误：

Generic parameter 'T' could not be inferred

这是代码：

// Gets User signed-in
func getUser() async throws -> AuthUser {
    do {
        try await withUnsafeThrowingContinuation { continuation in
            if let user = Amplify.Auth.getCurrentUser() {
                continuation.resume(returning: user )
            }
        }
    } catch(let error) {
        print(error)
    }
}

这是为什么？

Answer 1

其实我的电话本来就不好，应该是这样的：

// Gets User signed-in
func getUser() async throws -> AuthUser {
    return try await withCheckedThrowingContinuation { (continuation: CheckedContinuation<AuthUser, Error>) in
        if let user = Amplify.Auth.getCurrentUser() {
            continuation.resume(returning: user)
        } else {
            signOut()
        }
    }
}

有关详细信息，请转到 here

无法推断通用参数 'T' - Swift 5.5

Generic parameter 'T' could not be inferred - Swift 5.5

swift

swiftui

amplify