如何将函数从父组件传递给类型为 assingable 的子组件
How to pass function from parent component to child component with type assingable
我是 TypeScript 的新手,我想将我的函数 onDogSelected
传递给子组件 <Dogs />
。
当我尝试时,我收到了这样的错误消息:
Type '{ onDogSelected: (e: any) => void; }' is not assignable to type 'IntrinsicAttributes & { children?: ReactNode; }'.Property 'onDogSelected' does not exist on type 'IntrinsicAttributes & { children?: ReactNode; }'.
我不知道这是什么意思。我想弄清楚,但仍然没有解决方案。
const HomePage: React.FC = () => {
const [dogSelected, setDogSelected] = useState("");
const onDogSelected = (e: any) => {
setDogSelected(e.target.value)
}
return (
<ApolloProvider client={client2}>
<Dogs onDogSelected={onDogSelected} />
{dogSelected && <span>{dogSelected}</span>}
</ApolloProvider>
);
};
export default HomePage;
React.FC
已弃用,您应该使用 React.FunctionComponent
.
React.FunctionComponent
是泛型。如果您不再期待,您应该将组件的 props 传递给它。
所以 Dogs
组件应该看起来像,
import { FunctionComponent } from "react";
const Dogs: FunctionComponent<DogsProps> = (props) => {
...
};
interface DogsProps {
onDogSelected(e: any): void;
}
您不必创建接口或类型,只需将其作为参数传递即可
const Dogs: FunctionComponent<{ onDogSelected(e: any): void; }> = (props) => {
我是 TypeScript 的新手,我想将我的函数 onDogSelected
传递给子组件 <Dogs />
。
当我尝试时,我收到了这样的错误消息:
Type '{ onDogSelected: (e: any) => void; }' is not assignable to type 'IntrinsicAttributes & { children?: ReactNode; }'.Property 'onDogSelected' does not exist on type 'IntrinsicAttributes & { children?: ReactNode; }'.
我不知道这是什么意思。我想弄清楚,但仍然没有解决方案。
const HomePage: React.FC = () => {
const [dogSelected, setDogSelected] = useState("");
const onDogSelected = (e: any) => {
setDogSelected(e.target.value)
}
return (
<ApolloProvider client={client2}>
<Dogs onDogSelected={onDogSelected} />
{dogSelected && <span>{dogSelected}</span>}
</ApolloProvider>
);
};
export default HomePage;
React.FC
已弃用,您应该使用 React.FunctionComponent
.
React.FunctionComponent
是泛型。如果您不再期待,您应该将组件的 props 传递给它。
所以 Dogs
组件应该看起来像,
import { FunctionComponent } from "react";
const Dogs: FunctionComponent<DogsProps> = (props) => {
...
};
interface DogsProps {
onDogSelected(e: any): void;
}
您不必创建接口或类型,只需将其作为参数传递即可
const Dogs: FunctionComponent<{ onDogSelected(e: any): void; }> = (props) => {