如何不断提问，直到满足c中必须满足条件的要求

Question

我正在在线使用 cs50 IDE 所以我也在顶部使用 cs50 库。我试图让它一直问“你还好吗？”这个问题。直到你说“y”或“n”（大写或小写）。

#include <cs50.h>
#include <stdio.h>

int main(void)
{
 
    char answer;
    do
    {
        char answer = get_char("are you okay Y/N ");
        if (answer == 'y' || answer == 'Y')
        {
            printf("you are okay");
        }
            else if (answer == 'n' || answer == 'N')
        {
            printf("you are not okay ");
        }

    }
   
    while(answer != 'y' || answer != 'Y' || answer != 'n' || answer != 'N');
    
}

Answer 1

学习 C 语言的布尔逻辑时，常识会让你走得更远。那就是：养成说出你写的台词的习惯loud/in你的脑袋：

while(answer != 'y' || answer != 'Y' || answer != 'n' || answer != 'N');

翻译成英语：

"while the answer is not y or it is not Y or it is not..."

在这里你应该闻到鱼的味道。正确的 English/logic 宁愿是：

"while the answer is not y and it is not Y and..."

抛开常识，De Morgan's Laws 是学习任何编程之前非常必要的先决知识。

如何不断提问，直到满足c中必须满足条件的要求

How to ask question continuously until it meets requirements of having to meet a condition in c

c

if-statement

conditional-statements

cs50