在 plpgsql 函数中声明 setof bigint 的类型并分配给 from select union
Declare type of setof bigint in plpgsql function and assign into from select union
以下代码目前适用于 PostgreSQL 13.3(通过 Supabase.io)。函数 get_owned_base_ids
和 get_bases_editable
的 return 类型都是 setof bigint
:
CREATE FUNCTION get_owned_base_ids()
returns setof bigint
stable
language sql
as $$
select id
from bases
where bases.owner_user_id = auth.uid();
$$;
-- CREATE FUNCTION get_bases_editable()
-- returns setof bigint
-- ... similar to get_owned_base_ids()
-- $$;
CREATE FUNCTION xyz (base_id bigint)
returns int
language plpgsql
as $$
BEGIN
IF base_id not in (select get_owned_base_ids() UNION select get_bases_editable()) THEN
-- note: actual function logic is simplified for this question
return 1;
END IF;
return 0;
END;
$$;
是否可以定义一组 bigint 并从 select 联合分配它?像这样:
CREATE FUNCTION xyz (base_id bigint)
returns int
language plpgsql
as $$
DECLARE
allowed_base_ids bigint; -- needs to be a setof
BEGIN
select into allowed_base_ids get_owned_base_ids() UNION select get_bases_editable();
IF kv.base_id not in allowed_base_ids THEN
-- note: actual function logic is simplified for this question
return 1;
END IF;
return 0;
END;
$$;
通常意义不大,占用内存多,结果集很大,但可以用数组:
DECLARE
allowed_base_ids bigint[];
BEGIN
allowed_base_ids := array(SELECT * FROM get_owned_base_ids()
UNION ALL
SELECT * FROM get_bases_editable());
IF kv.base_id <> ALL (allowed_base_ids) THEN
...
END IF;
END;
以下代码目前适用于 PostgreSQL 13.3(通过 Supabase.io)。函数 get_owned_base_ids
和 get_bases_editable
的 return 类型都是 setof bigint
:
CREATE FUNCTION get_owned_base_ids()
returns setof bigint
stable
language sql
as $$
select id
from bases
where bases.owner_user_id = auth.uid();
$$;
-- CREATE FUNCTION get_bases_editable()
-- returns setof bigint
-- ... similar to get_owned_base_ids()
-- $$;
CREATE FUNCTION xyz (base_id bigint)
returns int
language plpgsql
as $$
BEGIN
IF base_id not in (select get_owned_base_ids() UNION select get_bases_editable()) THEN
-- note: actual function logic is simplified for this question
return 1;
END IF;
return 0;
END;
$$;
是否可以定义一组 bigint 并从 select 联合分配它?像这样:
CREATE FUNCTION xyz (base_id bigint)
returns int
language plpgsql
as $$
DECLARE
allowed_base_ids bigint; -- needs to be a setof
BEGIN
select into allowed_base_ids get_owned_base_ids() UNION select get_bases_editable();
IF kv.base_id not in allowed_base_ids THEN
-- note: actual function logic is simplified for this question
return 1;
END IF;
return 0;
END;
$$;
通常意义不大,占用内存多,结果集很大,但可以用数组:
DECLARE
allowed_base_ids bigint[];
BEGIN
allowed_base_ids := array(SELECT * FROM get_owned_base_ids()
UNION ALL
SELECT * FROM get_bases_editable());
IF kv.base_id <> ALL (allowed_base_ids) THEN
...
END IF;
END;