Kusto 将括号从 JSON 数组删除到列表

Question

我有一个非常简单的问题，但是我似乎找不到答案。如何转换 json 数组变量

["one","two","three"]

转换成以下适合使用参数进行字符串搜索的格式 ?

"one","two","three"

谢谢智囊团....

Answer 1

您可以使用以下功能：

substring() - 从索引 1 开始，长度为 strlen()-2：https://docs.microsoft.com/en-us/azure/data-explorer/kusto/query/substringfunction; https://docs.microsoft.com/en-us/azure/data-explorer/kusto/query/strlenfunction
strcat_array(): https://docs.microsoft.com/en-us/azure/data-explorer/kusto/query/strcat-arrayfunction

例如：

print input = dynamic(["one","two","three"])
| project output1 = substring(input, 1, strlen(input)-2),
          output2 = strcat('"', strcat_array(input, '","'), '"')

output1	output2
"one","two","three"	"one","two","three"

Kusto 将括号从 JSON 数组删除到列表

Kusto remove bracket from JSON array to a list

sentinel

kql

azure-data-explorer