如何获得 运行 个唯一 ID

Question

我需要获取 运行 个唯一 ID

select ID, min(date_time)
,case when ID is null then 0 else 1 end as New_ID
,SUM(New_ID) over (order by ID) as runningTotal_ID
          from Table1
          Group by 1

或者如果我可以直接数数 select Id, count(Id) over (order by ID) as Running Total

但是绑定这个它给了我 10000...计数但只有 200 个 ID

谁能帮帮我！

Answer 1

您可以使用 dense_rank() 。 . .假设你想要它们 ids 是按顺序分配的：

select t1.*, dense_rank() over (order by id) as runningTotalId
from Table1 t1;

如果不是，您可以将第一个标记为使用累计和：

select t1.*,
       sum(case when seqnum = 1 then 1 else 0 end) over (order by datetime) as runningTotalId
from (select t1.*, 
             row_number() over (partition by id order by datetime) as seqnum
      from table1 t1
     ) t