Python 在字符串中查找文本

Question

我有以下要提取数据的字符串：

text_example = '\nExample text \nTECHNICAL PARTICULARS\nLength oa: ...............189.9m\nLength bp: ........176m\nBreadth moulded:  .......26.4m\nDepth moulded to main deck:  ....9.2m\n

我要提取的每个变量都以 \n
我要获取的值以冒号':'开头，后跟1个以上的点
当它不是以冒号后跟点开头时，我不想提取该值。

例如，我的首选输出如下：

LOA = 189.9
LBP = 176.0
BM = 26.4
DM = 9.2

Answer 1

您可以创建一个正则表达式并解决该解决方案-

re.findall(r'(\n|\n)([A-Za-z\s]*)(?:(\:\s*\.+))(\d*\.*\d*)',text_example)[2]

('\n', 'Breadth moulded', ':  .......', '26.4')

Answer 2

import re

text_example = '\nExample text \nTECHNICAL PARTICULARS\nLength oa: ...............189.9m\nLength bp: ........176m\nBreadth moulded:  .......26.4m\nDepth moulded to main deck:  ....9.2m\n'

# capture all the characters BEFORE the ':' character

variables = re.findall(r'(.*?):', text_example)

# matches all floats and integers (does not account for minus signs)

values = re.findall(r'(\d+(?:\.\d+)?)', text_example)

# zip into dictionary (this is assuming you will have the same number of results for both regex expression.

result = dict(zip(variables, values))

print(result)

--> {'Length oa': '189.9', 'Breadth moulded': '26.4', 'Length bp': '176', 'Depth moulded to main deck': '9.2'}

Python 在字符串中查找文本

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