运行异步条带化

Question

以下代码需要几秒钟的时间才能运行:

payments = stripe.PaymentIntent.list(limit=10000)

如何使上述代码运行异步？

我试过 await payments = stripe.PaymentIntent.list(limit=10000) 但我收到错误 SyntaxError: cannot assign to await expression

Answer 1

您可以通过调用异步函数在不等待的情况下启动它：

async function listPaymentIntents() {
  const payments = await stripe.PaymentIntent.list({limit: 10000});
  console.log('done!');
}

console.log('calling listPaymentIntents!');
listPaymentIntents();
console.log('called listPaymentIntents!');

是的，正如@Barmar 提到的，await 在价值方面处理承诺决议。

编辑：不是异步 python 专家，但这似乎映射到异步 Tasks 的概念。也许可以这样做：

async def listPaymentIntents():
  payments = stripe.PaymentIntent.list(limit=10000);
  return payments

task = asyncio.create_task(listPaymentIntents())

// await task # optional

Answer 2

import time
import asyncio       
import threading


async def myfunction():

    await asyncio.sleep(10) #  sleep for 10 seconds

    payments = stripe.PaymentIntent.list(limit=10000)


server=threading.Thread(target=asyncio.run, args=(myfunction(),))

server.start()

运行异步条带化

Running Stripe Asynchronously

python

multithreading

asynchronous

stripe-payments

运行 异步条带化

Running Stripe Asynchronously

python

multithreading

asynchronous

stripe-payments

运行异步条带化