二进制搜索字符串
BinarySearch toString
我想像在 TreeSet 中一样创建一个 toString。
例如,我的 toString 将打印如下内容:
Student{name='student1', dateOfBirth=2003-04-01, details='none'}, Student{name='student2', dateOfBirth=1999-05-11, details='none'},
但我想要这样的东西:
[Student{name='student1', dateOfBirth=2003-04-01, details='none'}, Student{name='student2', dateOfBirth=1999-05-11, details='none'}]
我的代码:
public String toString() {
StringBuffer string = new StringBuffer();
inorderPrint(root, string);
return string.toString();
}
private void inorderPrint(Node root, StringBuffer stringBuffer) {
if (root != null) {
inorderPrint(root.left, stringBuffer);
stringBuffer.append(root.value.toString() + ", ");
inorderPrint(root.right, stringBuffer);
}
}
要添加额外的字符,例如 [
,
]
,您可以在 inOrder 遍历中使用附加条件。
示例代码:
public String toString()
{
StringBuffer string = new StringBuffer();
string.append('[');
inorderPrint(root, string);
string.append(']');
return string.toString();
}
private void inorderPrint(Node root, StringBuffer stringBuffer)
{
if (root != null)
{
inorderPrint(root.left, stringBuffer);
stringBuffer.append(", ");
stringBuffer.append(root.value.toString());
stringBuffer.append(", ");
inorderPrint(root.right, stringBuffer);
}
}
我想像在 TreeSet 中一样创建一个 toString。 例如,我的 toString 将打印如下内容:
Student{name='student1', dateOfBirth=2003-04-01, details='none'}, Student{name='student2', dateOfBirth=1999-05-11, details='none'},
但我想要这样的东西:
[Student{name='student1', dateOfBirth=2003-04-01, details='none'}, Student{name='student2', dateOfBirth=1999-05-11, details='none'}]
我的代码:
public String toString() {
StringBuffer string = new StringBuffer();
inorderPrint(root, string);
return string.toString();
}
private void inorderPrint(Node root, StringBuffer stringBuffer) {
if (root != null) {
inorderPrint(root.left, stringBuffer);
stringBuffer.append(root.value.toString() + ", ");
inorderPrint(root.right, stringBuffer);
}
}
要添加额外的字符,例如 [
,
]
,您可以在 inOrder 遍历中使用附加条件。
示例代码:
public String toString()
{
StringBuffer string = new StringBuffer();
string.append('[');
inorderPrint(root, string);
string.append(']');
return string.toString();
}
private void inorderPrint(Node root, StringBuffer stringBuffer)
{
if (root != null)
{
inorderPrint(root.left, stringBuffer);
stringBuffer.append(", ");
stringBuffer.append(root.value.toString());
stringBuffer.append(", ");
inorderPrint(root.right, stringBuffer);
}
}