jest.spyOn 从副作用调用调用时不工作

Question

我有以下场景：

const doSomething = () => {
    const test = 1;

    doAnotherThing();
    return test + 1;
};

const doAnotherThing = () => {};

module.exports = {
    doSomething,
    doAnotherThing
};

这是我的测试：

const MyModule = require('./myModule');

describe('MyModule', () => {
    it('Should be able to spy another call', () => {
        const spy = jest.spyOn(MyModule, 'doAnotherThing');

        MyModule.doSomething();

        expect(spy).toHaveBeenCalledTimes(1);
    });
});

问题，有没有办法让 doSomething() 中的 doAnotherThing() 调用以某种方式被玩笑窥探，而不使用 rewire 等解决方案？

Answer 1

在此处找到解决方案：https://medium.com/welldone-software/jest-how-to-mock-a-function-call-inside-a-module-21c05c57a39f

为此重新定义了我的模块，现在可以使用了

const doSomething = () => {
    const test = 1;

    MyModule.doAnotherThing();
    return test + 1;
};

const doAnotherThing = () => {};

const MyModule = {
    doSomething: doSomething,
    doAnotherThing: doAnotherThing
};

export default MyModule;

jest.spyOn 从副作用调用调用时不工作

jest.spyOn is not working when called from a side effect call

javascript

spy

jestjs