使用基于另一个数组的对象动态过滤数组

Question

使用基于另一个数组的对象动态过滤数组。

我需要使用另一个数组来过滤主数组。但是过滤器数组只会包含几个或几个字段。

    var codes = [{
"title": "lore",
"city": "New York",
"desc": "lorem lorem",
"age": "32"
 },
{
    "title": "lore2 ",
    "city": "Santa Monica",
    "desc": "lorem2",
    "age": "20"
  }

];

let filter = [{
  "city": "New York"
}, {
  "age": "20"
},

...或更多过滤器。此过滤器由单击复选框的人动态创建。

]

Answer 1

也许这样的东西对你有用？

基本上循环遍历过滤器，然后还遍历单独的过滤器对象键值对并根据代码检查它们。

var codes = [{
  "title": "lore",
  "city": "New York",
  "desc": "lorem lorem",
  "age": "32"
},
{
  "title": "lore2 ",
  "city": "Santa Monica",
  "desc": "lorem2",
  "age": "20"
}];

var filters = [{"city": "New York"}, {"age": "32"}];


function filterByMultipleFilters(data, filters) {
  return data.filter(item => {
    // Loop through all filters and check the current item
    for (const filter of filters) {
      for (const [key, value] of Object.entries(filter)) {
        if (!item[key] || item[key] !== value)
          return false;
      }
    }
    return true;
  });
}

console.clear();
let result = filterByMultipleFilters(codes, filters);
console.log(result);

Answer 2

这应该有效

let codes = [{
    "title": "lore",
    "city": "New York",
    "desc": "lorem lorem",
    "age": "20"
  },
  {
    "title": "lore2 ",
    "city": "Santa Monica",
    "desc": "lorem2",
    "age": "20"
  }
];

let filter = [{
  "city": "New York"
}, {
  "age": "20"
}];

let res = codes.filter(code => {
  return filter.every(f => {
    const [key, value] = Object.entries(f)[0];
    return code[key] == value
  });
});

console.log(res)

Answer 3

试试下面的代码示例，我想你想要什么；

尝试直接获取过滤器 object 而不是另一个数组；

可变代码 = [{ "title": "传说", “城市”：“纽约”， "desc": "lorem lorem", “年龄”：“32” }, { “标题”：“传说2”， “城市”：“圣莫尼卡”， “desc”：“lorem2”， “年龄”：“20” } ];

let filters = [{
  "city": "Santa Monica"
}, {
  "age": "20"
}];

const filterCode = {};
filters.forEach(filter => {
  for (var key of Object.keys(filter))
    filterCode[key] = filter[key];
});
var filteredCodes = codes.filter(code => {
  for (var key of Object.keys(filterCode)) {
      if(code[key] !== filterCode[key])
        return false;
  }
  return true;
});

console.log(过滤代码);

Answer 4

您可以采用更易于使用的更好数据结构，而不是未知键。

结果你得到所有 keys/values 匹配的对象。

const
    codes = [{ title: "lore", city: "New York", desc: "lorem lorem", age: "32" }, { title: "lore2 ", city: "New York", desc: "lorem2", age: "20" }],
    filter = [{ key: "city", value: "New York" }, { key: "age", value: "20" }],
    result = codes.filter(o => filter.every(({ key, value }) => o[key] === value));

console.log(result);

使用基于另一个数组的对象动态过滤数组

Filter Array with objects based on another array dynamically

javascript

arrays

filter

array.prototype.map