获取具有组合索引的列表中的值

Question

coded = ['','','','','','','','','','',
        'a','b','c','d','e','f','g','h','i',
        'j','k','l','m','n','o','p','q','r',
        's','t','u','v','w','x','y','z',' ']

def decode(decode):
     out = ''
     for x in range(1, len(str(decode)) // 2):
          out += coded[int(str(decode[x * 2 - 2]) + str(decode[x * 2 - 1]))]  #here is the issue
     return out

print(decode(16133335202320))

我正在尝试从输入值中每 2 个字符的列表中获取一个值。但是，在我评论的地方，它不断提出“int”对象不可订阅。

我该如何解决这个问题？

Answer 1

您必须先将数字转换为字符串：

>>> print(decode(16133335202320))
...
TypeError: 'int' object is not subscriptable


#         HERE ---v
>>> print(decode(str(16133335202320)))
gdxzkn

或

您可以像下面这样重写您的函数：

def decode(decode):
     decode = str(decode)
     out = ''
     for x in range(1, len(decode) // 2):
          out += coded[int(decode[x * 2 - 2] + decode[x * 2 - 1])]
     return out

>>> print(decode(16133335202320))
gdxzkn

Answer 2

此答案基于 fischmalte 的评论：

coded = ['','','','','','','','','','',
        'a','b','c','d','e','f','g','h','i',
        'j','k','l','m','n','o','p','q','r',
        's','t','u','v','w','x','y','z',' ']

def decode(decode):
    out = ''
    for x in range(1, len(str(decode)) // 2):
        out += coded[int(str(decode)[x * 2 - 2] + str(decode)[x * 2 - 1])] ### EDITED LINE
    return out

print(decode(16133335202320))

将 str(decode[x * 2 - 2]) 更改为 str(decode)[x * 2 - 2]，将 str(decode[x * 2 - 1]) 更改为 str(decode)[x * 2 - 1]。

获取具有组合索引的列表中的值

getting the value on a list with a combined index

python

integer

list