MongoDb 仅当数组不为空时才在数组中添加字段
MongoDb Add field in array only is the arry is not null
现在我有一个新的情况3.0版。
我有这个假的 json:
[
{
"type":"PF",
"code":12345,
"Name":"Darth Vader",
"currency":"BRL",
"status":"ACTIVE",
"localization":"NABOO",
"createDate":1627990848665,
"olderAdress":[
{
"localization":"DEATH STAR",
"status":"BLOCKED",
"createDate":1627990848665
},
{
"localization":"TATOOINE",
"status":"CANCELLED",
"createDate":1627990555665
},
{
"localization":"ALDERAAN",
"status":"INACTIVED",
"createDate":1627990555665
}
]
},
{
"type":"PF",
"code":12345,
"Name":"Anakin Skywalker",
"currency":"BRL",
"status":"ACTIVE",
"localization":"NABOO",
"createDate":1627990848665,
"olderAdress":null
}
]
并且我需要在每个数组元素中添加一个新字段仅当数组不为空时。但我需要通过聚合来做到这一点,因为在发送给用户之前,我在 Spring 中使用了这个结果。
我需要这个结果:
[
{
"type": "PF",
"code": 12345,
"Name": "Darth Vader",
"currency": "BRL",
"status": "ACTIVE",
"localization": "NABOO",
"createDate": 1627990848665,
"olderAddress": [
{
"localization": "DEATH STAR",
"status": "BLOCKED",
"createDate": 1627990848665,
"isItemOfOlderAddress" : true
},
{
"localization": "TATOOINE",
"status": "CANCELLED",
"createDate": 1627990555665,
"isItemOfOlderAddress" : true
},
{
"localization": "ALDERAAN",
"status": "INACTIVED",
"createDate": 1627990555665,
"isItemOfOlderAddress" : true
},
]
},
{
"type": "PF",
"code": 12345,
"Name": "Anakin Skywalker",
"currency": "BRL",
"status": "ACTIVE",
"localization": "NABOO",
"createDate": 1627990848665,
"olderAdress": null
},
]
所以我添加字段 isItemOfOlderAddress 仅在 olderAddress 不为 null 且 olderAddress 为 null 的地方我只显示默认信息。我该怎么做?
查询
- 如果 olderAdress 是
array
(因此 null
也不是),请将 "isItemOfOlderAddress": true
字段添加到所有成员
- 否则保留旧值(因此也保留
null
)
db.collection.aggregate([
{
"$set": {
"olderAdress": {
"$cond": [
{
"$isArray": [
"$olderAdress"
]
},
{
"$map": {
"input": "$olderAdress",
"in": {
"$mergeObjects": [
"$$this",
{
"isItemOfOlderAddress": true
}
]
}
}
},
"$olderAdress"
]
}
}
}
])
现在我有一个新的情况3.0版。 我有这个假的 json:
[
{
"type":"PF",
"code":12345,
"Name":"Darth Vader",
"currency":"BRL",
"status":"ACTIVE",
"localization":"NABOO",
"createDate":1627990848665,
"olderAdress":[
{
"localization":"DEATH STAR",
"status":"BLOCKED",
"createDate":1627990848665
},
{
"localization":"TATOOINE",
"status":"CANCELLED",
"createDate":1627990555665
},
{
"localization":"ALDERAAN",
"status":"INACTIVED",
"createDate":1627990555665
}
]
},
{
"type":"PF",
"code":12345,
"Name":"Anakin Skywalker",
"currency":"BRL",
"status":"ACTIVE",
"localization":"NABOO",
"createDate":1627990848665,
"olderAdress":null
}
]
并且我需要在每个数组元素中添加一个新字段仅当数组不为空时。但我需要通过聚合来做到这一点,因为在发送给用户之前,我在 Spring 中使用了这个结果。
我需要这个结果:
[
{
"type": "PF",
"code": 12345,
"Name": "Darth Vader",
"currency": "BRL",
"status": "ACTIVE",
"localization": "NABOO",
"createDate": 1627990848665,
"olderAddress": [
{
"localization": "DEATH STAR",
"status": "BLOCKED",
"createDate": 1627990848665,
"isItemOfOlderAddress" : true
},
{
"localization": "TATOOINE",
"status": "CANCELLED",
"createDate": 1627990555665,
"isItemOfOlderAddress" : true
},
{
"localization": "ALDERAAN",
"status": "INACTIVED",
"createDate": 1627990555665,
"isItemOfOlderAddress" : true
},
]
},
{
"type": "PF",
"code": 12345,
"Name": "Anakin Skywalker",
"currency": "BRL",
"status": "ACTIVE",
"localization": "NABOO",
"createDate": 1627990848665,
"olderAdress": null
},
]
所以我添加字段 isItemOfOlderAddress 仅在 olderAddress 不为 null 且 olderAddress 为 null 的地方我只显示默认信息。我该怎么做?
查询
- 如果 olderAdress 是
array
(因此null
也不是),请将"isItemOfOlderAddress": true
字段添加到所有成员 - 否则保留旧值(因此也保留
null
)
db.collection.aggregate([
{
"$set": {
"olderAdress": {
"$cond": [
{
"$isArray": [
"$olderAdress"
]
},
{
"$map": {
"input": "$olderAdress",
"in": {
"$mergeObjects": [
"$$this",
{
"isItemOfOlderAddress": true
}
]
}
}
},
"$olderAdress"
]
}
}
}
])