我正在创建一个（非常粗糙的）计算器，想知道这段代码有什么问题

Question

# Pick the numbers you'd like to use
number1 = (input('What is the first number?\n'))
number2 = (input('What is the second number?\n'))
# Choose what to do with those numbers
Choice = input('Would you like to add, subtract, multiply or divide?\n ')
# Where the calculating happens, if it doesn't go through the error message asking you to use numbers will happen
try :
  # Converting the numbers from str into float, if this doesnt happen it means numbers were not used
  num1 = float(number1)
  num2 = float(number2)
  if Choice is add :
    answer = num1 + num2
    elif Choice is subtract : 
      answer = num1 - num2
        elif Choice is divide :
          answer = num1/num2
            elif Choice is multiply
              answer = num1 * num2
print(answer)

# The error message if the numbers you gave werent in numeric form
except :
  print('Please choose proper numbers in numeric form instead of letter/words')

这是代码，我遇到的问题是：

'文件“main.py”，第 13 行 elif 选择是 subtract ： ^ 语法错误：语法无效'

如有任何帮助，我们将不胜感激，谢谢 :)。（如果这段代码根本不起作用，请 lmk。我正在阅读一本关于如何编码的书，我认为尝试这会很有趣，因为我刚刚了解了布尔值和变量）

Answer 1

我想你的意思是：

if Choice == 'add':
    answer = num1 + num2
elif Choice == 'subtract': 
    answer = num1 - num2
elif Choice == 'divide':
    answer = num1/num2
elif Choice == 'multiply':
    answer = num1 * num2

注意缩进。如果你有一个单独的 if / elseif / elseif / elseif / else 链，每个条件都应该处于相同的缩进级别，并且每个主体都应该匹配它的条件加上一个缩进（通常是 4 个空格或 1 个制表符）。

要将使用 input() 从用户那里捕获的字符串与文字字符串进行比较，您可以这样做：

if Choice == 'add':

您需要在 'add' 周围指定引号，否则它会尝试引用名为 add 的变量，该变量未定义。

对于 == 与 is 检查字符串时，请参阅 Why does comparing strings using either '==' or 'is' sometimes produce a different result?

我正在创建一个（非常粗糙的）计算器，想知道这段代码有什么问题

I'm creating a (very crude) calculator and would like to know what's wrong with this code

python

syntax

calculator

syntax-error