如何 - 按键对列表进行分组并使用流拆分值 Java 8
How to - grouping a list by key and split the values using streams Java 8
我需要对ABC List进行分组,同时我还想拆分值。
输入:
List<ABC> list = new ArrayList<>();
ABC A1 = new ABC();
A1.setName("OO");
A1.setVal("OO111,OO222,OO333"); // split this while grouping
list.add(A1);
ABC A2 = new ABC();
A2.setName("OO");
A2.setVal("OO1");
list.add(A2);
ABC A3 = new ABC();
A3.setName("YY");
A3.setVal("1333,11444");
list.add(A3);
Output:
```java
Map<String, List<String>> postsPerType;
//Group by Name: ex: OO & YY. Split the Value by "," and add it to list
Key: 00 Values: List: "OO111","OO222","OO333","OO1"
Key: YY Values: List: "1333","11444"
求推荐,谢谢
我认为您可以将 reducing
收集器链接到 groupingBy
收集器以获得您需要的东西:
Map<String, List<String>> postsPerType =
list.stream()
.collect(Collectors.groupingBy(ABC::getName,
Collectors.reducing(new ArrayList<String>(),
a -> Arrays.asList(a.getVal().split(",")),
(l1,l2)-> {
List<String> l = new ArrayList<>();
l.addAll(l1);
l.addAll (l2);
return l;
})));
这会产生以下结果 Map
:
{YY=[1333, 11444], OO=[OO111, OO222, OO333, OO1]}
如果您使用 Java 9+,您可以使用 Collectors.flatMapping()
作为 groupingBy
的下游:
list.stream().collect(Collectors.groupingBy(ABC::getName,
Collectors.flatMapping(a -> Arrays.stream(a.getVal().split(",")),
Collectors.toList())));
这应该会产生您想要的结果。
另一种方法是使用 groupingBy
和 collectingAndThen
收集器。
list.stream()
.collect(Collectors.groupingBy(
ABC::getName,
Collectors.collectingAndThen(
Collectors.mapping(ABC::getVal, toList()),
strings -> strings.stream()
.flatMap(s -> Arrays.stream(s.split(",")))
.collect(toList()))
));
试试这个。
record ABC(String name, String val) {
public String getName() { return name; }
public String getVal() { return val; }
}
public static void main(String[] args) {
List<ABC> list = List.of(
new ABC("00", "00111,00222,00333"),
new ABC("00", "001"),
new ABC("YY", "1333,11444"));
Map<String, List<String>> postsPerType = new HashMap<>();
for (ABC e : list)
postsPerType.computeIfAbsent(e.getName(), k -> new ArrayList<>())
.addAll(Arrays.asList(e.getVal().split(",")));
System.out.println(postsPerType);
}
输出:
{YY=[1333, 11444], 00=[00111, 00222, 00333, 001]}
我需要对ABC List进行分组,同时我还想拆分值。 输入:
List<ABC> list = new ArrayList<>();
ABC A1 = new ABC();
A1.setName("OO");
A1.setVal("OO111,OO222,OO333"); // split this while grouping
list.add(A1);
ABC A2 = new ABC();
A2.setName("OO");
A2.setVal("OO1");
list.add(A2);
ABC A3 = new ABC();
A3.setName("YY");
A3.setVal("1333,11444");
list.add(A3);
Output:
```java
Map<String, List<String>> postsPerType;
//Group by Name: ex: OO & YY. Split the Value by "," and add it to list
Key: 00 Values: List: "OO111","OO222","OO333","OO1"
Key: YY Values: List: "1333","11444"
求推荐,谢谢
我认为您可以将 reducing
收集器链接到 groupingBy
收集器以获得您需要的东西:
Map<String, List<String>> postsPerType =
list.stream()
.collect(Collectors.groupingBy(ABC::getName,
Collectors.reducing(new ArrayList<String>(),
a -> Arrays.asList(a.getVal().split(",")),
(l1,l2)-> {
List<String> l = new ArrayList<>();
l.addAll(l1);
l.addAll (l2);
return l;
})));
这会产生以下结果 Map
:
{YY=[1333, 11444], OO=[OO111, OO222, OO333, OO1]}
如果您使用 Java 9+,您可以使用 Collectors.flatMapping()
作为 groupingBy
的下游:
list.stream().collect(Collectors.groupingBy(ABC::getName,
Collectors.flatMapping(a -> Arrays.stream(a.getVal().split(",")),
Collectors.toList())));
这应该会产生您想要的结果。
另一种方法是使用 groupingBy
和 collectingAndThen
收集器。
list.stream()
.collect(Collectors.groupingBy(
ABC::getName,
Collectors.collectingAndThen(
Collectors.mapping(ABC::getVal, toList()),
strings -> strings.stream()
.flatMap(s -> Arrays.stream(s.split(",")))
.collect(toList()))
));
试试这个。
record ABC(String name, String val) {
public String getName() { return name; }
public String getVal() { return val; }
}
public static void main(String[] args) {
List<ABC> list = List.of(
new ABC("00", "00111,00222,00333"),
new ABC("00", "001"),
new ABC("YY", "1333,11444"));
Map<String, List<String>> postsPerType = new HashMap<>();
for (ABC e : list)
postsPerType.computeIfAbsent(e.getName(), k -> new ArrayList<>())
.addAll(Arrays.asList(e.getVal().split(",")));
System.out.println(postsPerType);
}
输出:
{YY=[1333, 11444], 00=[00111, 00222, 00333, 001]}