当前函数拥有的值引用数据
Value referencing data owned by the current function
这是我的代码:
struct Something<'a> {
val: u32,
another: &'a AnotherThing,
}
struct AnotherThing {
val: u32,
}
impl Default for AnotherThing {
fn default() -> Self {
Self {
val: 2,
}
}
}
trait Anything {
fn new(val: u32) -> Self;
}
impl Anything for Something<'_> {
fn new(val: u32) -> Self {
Self {
val,
another: &AnotherThing::default(),
}
}
}
fn main() {
let _ = Something::new(1);
}
无法编译因为:
Compiling playground v0.0.1 (/playground)
error[E0515]: cannot return value referencing temporary value
--> src/main.rs:24:9
|
24 | / Self {
25 | | val,
26 | | another: &AnotherThing::default(),
| | ----------------------- temporary value created here
27 | | }
| |_________^ returns a value referencing data owned by the current function
我了解问题,但不知道如何解决。如果在这种情况下无法使用 Default 特征,我该如何处理函数所有权。下面是一个更简单的例子:
struct Something<'a> {
val: u32,
another: &'a AnotherThing,
}
struct AnotherThing {
val: u32,
}
trait Anything {
fn new(val: u32) -> Self;
}
impl Anything for Something<'_> {
fn new(val: u32) -> Self {
let at = AnotherThing { val : 2 };
Self {
val,
another: &at,
}
}
}
fn main() {
let _ = Something::new(1);
}
如果我有 another: &AnotherThing { val : 2 }
而不是 another: &at
就可以了。如果我想让 another
属性成为引用并从函数中获取值,我该怎么做?
你可以这样做
#[derive(Default)]
struct Something<'a> {
val: u32,
another: &'a AnotherThing,
}
struct AnotherThing {
val: u32,
}
impl<'a> Default for &'a AnotherThing {
fn default() -> &'a AnotherThing {
&AnotherThing {
val: 3,
}
}
}
trait Anything {
fn new(val: u32) -> Self;
}
impl Anything for Something<'_> {
fn new(val: u32) -> Self {
Self {
val,
..Default::default()
}
}
}
另一种选择是创建一个 const
项目,您可以创建一个具有 'static
生命周期的引用,从而绑定到任何 'a
:
struct Something<'a> {
val: u32,
another: &'a AnotherThing,
}
struct AnotherThing {
val: u32,
}
const ANOTHER_THING_DEFAULT: AnotherThing = AnotherThing { val: 3 };
trait Anything {
fn new(val: u32) -> Self;
}
impl Anything for Something<'_> {
fn new(val: u32) -> Self {
Self {
val,
another: &ANOTHER_THING_DEFAULT,
}
}
}
这是我的代码:
struct Something<'a> {
val: u32,
another: &'a AnotherThing,
}
struct AnotherThing {
val: u32,
}
impl Default for AnotherThing {
fn default() -> Self {
Self {
val: 2,
}
}
}
trait Anything {
fn new(val: u32) -> Self;
}
impl Anything for Something<'_> {
fn new(val: u32) -> Self {
Self {
val,
another: &AnotherThing::default(),
}
}
}
fn main() {
let _ = Something::new(1);
}
无法编译因为:
Compiling playground v0.0.1 (/playground)
error[E0515]: cannot return value referencing temporary value
--> src/main.rs:24:9
|
24 | / Self {
25 | | val,
26 | | another: &AnotherThing::default(),
| | ----------------------- temporary value created here
27 | | }
| |_________^ returns a value referencing data owned by the current function
我了解问题,但不知道如何解决。如果在这种情况下无法使用 Default 特征,我该如何处理函数所有权。下面是一个更简单的例子:
struct Something<'a> {
val: u32,
another: &'a AnotherThing,
}
struct AnotherThing {
val: u32,
}
trait Anything {
fn new(val: u32) -> Self;
}
impl Anything for Something<'_> {
fn new(val: u32) -> Self {
let at = AnotherThing { val : 2 };
Self {
val,
another: &at,
}
}
}
fn main() {
let _ = Something::new(1);
}
如果我有 another: &AnotherThing { val : 2 }
而不是 another: &at
就可以了。如果我想让 another
属性成为引用并从函数中获取值,我该怎么做?
你可以这样做
#[derive(Default)]
struct Something<'a> {
val: u32,
another: &'a AnotherThing,
}
struct AnotherThing {
val: u32,
}
impl<'a> Default for &'a AnotherThing {
fn default() -> &'a AnotherThing {
&AnotherThing {
val: 3,
}
}
}
trait Anything {
fn new(val: u32) -> Self;
}
impl Anything for Something<'_> {
fn new(val: u32) -> Self {
Self {
val,
..Default::default()
}
}
}
另一种选择是创建一个 const
项目,您可以创建一个具有 'static
生命周期的引用,从而绑定到任何 'a
:
struct Something<'a> {
val: u32,
another: &'a AnotherThing,
}
struct AnotherThing {
val: u32,
}
const ANOTHER_THING_DEFAULT: AnotherThing = AnotherThing { val: 3 };
trait Anything {
fn new(val: u32) -> Self;
}
impl Anything for Something<'_> {
fn new(val: u32) -> Self {
Self {
val,
another: &ANOTHER_THING_DEFAULT,
}
}
}