字典理解中的海象运算符

Question

我想避免在字典理解中对均值进行双重计算，我尝试使用海象运算符：

>>> dic = {"A": [45,58,75], "B": [55,82,80,92], "C": [78,95,90], "D":[98,75]}
>>> q = {x: (mean := (sum(dic[x]) // len(dic[x]))) for x in dic if mean > 65}

但这给了我以下错误：

Traceback (most recent call last):
  File "<pyshell#2>", line 1, in <module>
    q = {x: (mean := (sum(dic[x]) // len(dic[x]))) for x in dic if mean > 65}
  File "<pyshell#2>", line 1, in <dictcomp>
    q = {x: (mean := (sum(dic[x]) // len(dic[x]))) for x in dic if mean > 65}
  NameError: name 'mean' is not defined

此错误仅在我尝试使用变量时发生，定义时没有问题：

>>> q = {x: (mean := (sum(dic[x]) // len(dic[x]))) for x in dic if (sum(dic[x]) // len(dic[x])) > 65}
>>> mean
86
>>> q
{'B': 77, 'C': 87, 'D': 86}

为什么？我哪里弄错了？

Answer 1

您需要将赋值表达式放在理解的条件中，而不是字典的值部分：

dic = {"A": [45,58,75], "B": [55,82,80,92], "C": [78,95,90], "D":[98,75]}
q = {x:mean for x in dic if (mean := (sum(dic[x]) // len(dic[x]))) > 65}

输出：

{'B': 77, 'C': 87, 'D': 86}

Answer 2

您的代码大致等同于

q = {}
for x in dic:
    if mean > 65:
        mean := ...
        q[x] = mean

这意味着您在分配之前使用 mean。

您需要将定义移动到 dict-comprehension 的 if-clause-section。

>>> dic = {"A": [45,58,75], "B": [55,82,80,92], "C": [78,95,90], "D":[98,75]}
>>> q = {x: mean for x in dic if (mean := (sum(dic[x]) // len(dic[x]))) > 65}
>>> q
{'B': 77, 'C': 87, 'D': 86}

这转化为

q = {}
for x in dic:
    if (mean := ...) > 65:
        q[x] = mean

字典理解中的海象运算符

walrus operator in dict comprehension

python

dictionary-comprehension

python-3.9

walrus-operator