如何从 bazel sh_binary 调用 bash 函数？

Question

我想从 sh_binary 调用 bash 函数，但不知道如何调用。

我有 bash 个带有函数调用的脚本：

mybashfunction.sh

function a () {
  echo a
}

function b () {
  echo b
}

BUILD.bazel

sh_binary(
    name = "a",
    srcs = ["mybashfunction.sh"],
    args = [
        "a",
    ],
    visibility = ["//visibility:public"],
)

以下运行不调用 bash 函数：

bazel run //test:a

Returns:

INFO: Analyzed target //test:a (0 packages loaded, 0 targets configured).
INFO: Found 1 target...
Target //test:a up-to-date:
  bazel-bin/test/a
INFO: Elapsed time: 0.148s, Critical Path: 0.00s
INFO: 1 process: 1 internal.
INFO: Build completed successfully, 1 total action
INFO: Build completed successfully, 1 total action

使它工作的唯一方法是从另一个脚本调用该函数：

a.sh

source ./test/mybashfunction.sh
a

BUILD.bazel

sh_binary(
    name = "a",
    srcs = ["a.sh"],
    data = [
        "mybashfunction.sh",
    ],
    visibility = ["//visibility:public"],
)

输出：

bazel run //test:a
INFO: Analyzed target //test:a (1 packages loaded, 3 targets configured).
INFO: Found 1 target...
Target //test:a up-to-date:
  bazel-bin/test/a
INFO: Elapsed time: 0.192s, Critical Path: 0.02s
INFO: 4 processes: 4 internal.
INFO: Build completed successfully, 4 total actions
INFO: Build completed successfully, 4 total actions
a

Answer 1

这不是最干净的方法，但一种可能的解决方案是扩展您的脚本以接受函数运行作为参数，例如

function a () {
  echo a
}

function b () {
  echo b
}

if [ ! -z "" ]; then
  
fi

由于您将参数传递给 BUILD 文件中的脚本，这应该会触发对函数的调用：

sh_binary(
    name = "a",
    srcs = ["mybashfunction.sh"],
    args = [
        "a",
    ],
    visibility = ["//visibility:public"],
)

sh_binary(
    name = "b",
    srcs = ["mybashfunction.sh"],
    args = [
        "b",
    ],
    visibility = ["//visibility:public"],
)

$> bazel run :a
...
INFO: Build completed successfully, 1 total action
a

$> bazel run :b
...
INFO: Build completed successfully, 1 total action
b

如何从 bazel sh_binary 调用 bash 函数？

How do I call a bash function from bazel sh_binary?

bash

bazel