SQL 获取利润最少的日期

Question

目前我正在查询以获取利润最少的日期。我为此使用的 table 是这个：

我想出的查询找到利润最少的日期，但没有显示当天赚取的金额的总和：

SELECT MIN(PRICE*QUANTITY) AS UMSATZ, ORDER_DATE
FROM FACT_ORDER
GROUP BY ORDER_DATE
ORDER BY UMSATZ
LIMIT 1;

所以结果是：

哪个查询可以额外显示当天盈利的SUM金额（不加一列）？非常感谢您！

Answer 1

Which query could show the SUM amount of the profit made that day in addition (not with an additional column)?

总计：

SELECT DISTINCT ORDER_DATE,
     SUM(PRICE*QUANTITY) OVER(PARTITION BY ORDER_DATE) AS UMSATZ 
FROM FACT_ORDER
QUALIFY (PRICE*QUANTITY) = MIN(PRICE*QUANTITY) OVER(PARTITION BY ORDER_DATE);

Answer 2

您可以通过自联接实现此目的。

select umsatz, a.order_date, sumUmsatz from (
    select 
    min(price*quantity) as umsatz, order_date
    from FACT_ORDER 
    group by datum order by min(price*quantity)asc
)a inner join (
    select sum(price*quantity) as sumUmsatz, order_date from 
    FACT_ORDER group by order_date
) b on a.order_date = b.order_date
where rownum = 1;

SQL 获取利润最少的日期

SQL get the date with the least profit made

sql

group-by

sql-order-by

min

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