首先按文本排序，然后按字母数字字符串上的数字排序

Question

我有一个这样的数组

["1","0K","11",1,"KE","PQ",5,"5"]

我希望它先按文本排序，然后按数字排序，如下所示

["KE","PQ","0K","1",1,5,"5","11"]

我用了local compare，但好像没用。

function desc(a,b){
  //below is the code that needs improvement
  return b.toString().localeCompare(a, undefined, {
    numeric: true,
    sensitivity: "base",
  });
}

function sort(order) {
  return order === "desc"
    ? (a, b) => desc(a, b)
    : (a, b) => -desc(a, b);
}

function stableSort(array, cmp){
  const stabilizedThis = array.map((el, index) => [el, index]);
  stabilizedThis.sort((a, b) => {
    const order = cmp(a[0], b[0]);
    if (order !== 0) return order;
    return (a[1]) - (b[1]);
  });
  return stabilizedThis.map((el) => el[0]);
}

var arr = ["1","0K","11",1,"KE","PQ",5,"5"];
console.log(stableSort(arr, sort("asc")))

Answer 1

您可以编写 filter 方法来获取 strings containing numbers，删除条目，从 rest 中分别获取 numbers 和 strings，然后对它们进行排序以你喜欢的方式。

const data = ["1","0K","11",1,"KE","PQ",5,"5"];

const stringsWithNumbers = data.filter(x => /\d+[a-zA-Z]/.test(x));

const rest = data.filter(x => !stringsWithNumbers.includes(x));

const numbers = rest.filter((x) => parseInt(x, 10));
const words = rest.filter((x) => !parseInt(x, 10));

const result = [
  ...words.sort((a, b) => a.localeCompare(b)), 
  ...stringsWithNumbers.concat(numbers).sort((a, b) => parseInt(a) - parseInt(b)),
];

console.log(result);

Answer 2

const sort = (arr = []) => {
  const nonAlpha = /[^a-zA-Z]/g, nonNum = /[^0-9]/g;
  return arr.sort((a, b) => {
    const aStr = String(a), bStr = String(b);
    const aAlpha = aStr.replace(nonAlpha, ""), bAlpha = bStr.replace(nonAlpha, "");
    const alphaCompare = bAlpha.localeCompare(aAlpha);
    if(alphaCompare) return alphaCompare;
    const aNum = +aStr.replace(nonNum, ""), bNum = +bStr.replace(nonNum, "");
    return aNum - bNum;
  });
}

console.log( sort(["1","0K","11",1,"KE","PQ",5,"5"]) );

Answer 3

    var arr = ["1","OK","11",1,"KE","PQ",5,"5"]
    var wordArr = []
    var numArr = []
    arr.forEach((el) => {
        if(Number(el)){
            numArr.push(el)
        } else {
            wordArr.push(el)
        }
    });
    wordArr.sort()
    numArr.sort((a, b) => a - b)
    arr = wordArr.concat(numArr)
    console.log(arr)

首先按文本排序，然后按字母数字字符串上的数字排序

Sorting first by text then by number on alpha numeric strings

javascript

arrays

sorting

alphanumeric