对列然后按 ORDER BY

Question

这一定是一个 PEBCAK 问题，因为它看起来很基础。是否有查询说，“如果 'mon' = 1 THEN ORDER BY 'time' THEN if 'tue' = 1 ORDER BY 'time', THEN if 'wed' = 1按 'time' 排序" ?

+=====+=====+=====+========+
| mon | tue | wed |  time  |
+=====+=====+=====+========+
|  0  |  1  |  1  |  0100  |
|  0  |  0  |  0  |  2200  |
|  1  |  1  |  1  |  1500  |
|  1  |  1  |  0  |  0600  |
|  0  |  0  |  0  |  1400  |
|  1  |  0  |  1  |  1100  |
+=====+=====+=====+========+

想要的结果：

mon 0600
mon 1100
mon 1500
tue 0100
tue 0600
tue 1500
wed 0100
wed 1100
wed 1500

Answer 1

...
ORDER BY CASE WHEN mon=1 THEN 1 WHEN tue=1 THEN 2 WHEN wed=1 THEN 3 END,
    time

对列然后按 ORDER BY

Pair Columns then ORDER BY

mysql

sql-order-by