在 React 组件中使用异步函数、等待和解析
Using async function, await and resolve in React component
我有一个具有以下结构的组件:
const _dbCall = () => {
const fooDb = SQLite.openDatabase(db);
return new Promise(resolve => {
fooDb.transaction(tx => {
tx.executeSql(`SOME SQL`, [], (tx, results) => {
resolve(results.rows._array);
}, null);
});
})
}
async function _renderSomething() {
const results = await _dbCall();
return <FlatList
data={results}
renderItem={_renderFunc}
keyExtractor={item => item} />
}
我在Component
的render()
函数中使用了_renderSomething()
。
然而,这给了我:
Error: Objects are not valid as a React child (found: object with keys {_U, _V, _W, _X}). If you meant to render a collection of children, use an array instead.
这个{_U, _V, _W, _X}
对我来说看起来像是一个悬而未决的承诺。
当我从 renderSomething()
中删除 async
关键字时,注释 const results = ...
并将一些虚拟数据传递给 <FlatList ...
,它呈现没有问题。
为什么 renderSomething()
不是 return <FlatList ...
而是一个悬而未决的承诺?
您可以在 useEffect
挂钩中使用。
function _renderSomething() {
const [data,setData] = React.useState([])
React.useEffect(()=>{
(async () => {
const results = await _dbCall();
setData(results);
})()
}, []);
return <FlatList
data={data}
renderItem={_renderFunc}
keyExtractor={item => item} />
}
正如@Yousaf 指出的那样:
const [resultsFromDb, setResultsFromDb] = useState([]);
const _dbCall = () => {
const foo = [];
const fooDb = SQLite.openDatabase(db);
fooDb.transaction(tx => {
tx.executeSql(`SOME SQL`, [], (tx, results) => {
// do something the results
for (let i = 0; i < results.rows.length; i++) {
foo.push(results.rows.item(i));
}
setResultsFromDb(foo)
}, null);
});
}
const _renderSomething = () => {
const results = _dbCall();
return <FlatList
data={resultsFromDb}
renderItem={_renderFunc}
keyExtractor={item => item} />
}
我有一个具有以下结构的组件:
const _dbCall = () => {
const fooDb = SQLite.openDatabase(db);
return new Promise(resolve => {
fooDb.transaction(tx => {
tx.executeSql(`SOME SQL`, [], (tx, results) => {
resolve(results.rows._array);
}, null);
});
})
}
async function _renderSomething() {
const results = await _dbCall();
return <FlatList
data={results}
renderItem={_renderFunc}
keyExtractor={item => item} />
}
我在Component
的render()
函数中使用了_renderSomething()
。
然而,这给了我:
Error: Objects are not valid as a React child (found: object with keys {_U, _V, _W, _X}). If you meant to render a collection of children, use an array instead.
这个{_U, _V, _W, _X}
对我来说看起来像是一个悬而未决的承诺。
当我从 renderSomething()
中删除 async
关键字时,注释 const results = ...
并将一些虚拟数据传递给 <FlatList ...
,它呈现没有问题。
为什么 renderSomething()
不是 return <FlatList ...
而是一个悬而未决的承诺?
您可以在 useEffect
挂钩中使用。
function _renderSomething() {
const [data,setData] = React.useState([])
React.useEffect(()=>{
(async () => {
const results = await _dbCall();
setData(results);
})()
}, []);
return <FlatList
data={data}
renderItem={_renderFunc}
keyExtractor={item => item} />
}
正如@Yousaf 指出的那样:
const [resultsFromDb, setResultsFromDb] = useState([]);
const _dbCall = () => {
const foo = [];
const fooDb = SQLite.openDatabase(db);
fooDb.transaction(tx => {
tx.executeSql(`SOME SQL`, [], (tx, results) => {
// do something the results
for (let i = 0; i < results.rows.length; i++) {
foo.push(results.rows.item(i));
}
setResultsFromDb(foo)
}, null);
});
}
const _renderSomething = () => {
const results = _dbCall();
return <FlatList
data={resultsFromDb}
renderItem={_renderFunc}
keyExtractor={item => item} />
}