如何连接两个查询结果并根据条件过滤掉数据？

Question

我是运行两个 sql 正在提供一些输出的查询。我想把它们结合起来，根据需求筛选出结果。

说明-

查询 1：

select `Project Number` from vw_onco_pharma onco_pharma union select `Project Number` from vw_onco_cell_gene cell_gene union select `Project Number` from vw_non_onco_cell_gene onco_cell_gene union select `Project Number` from vw_non_onco_pharma non_onco_pharma union select `Project Number` from vw_plasma_protein plasma_protein

输出 1：

Project Number
S100
S100
S200
S300
S300
S300
S400
S400

查询 2： select Project Number 来自 FCT_HTA_ONC_NONONC_PGMS;

输出 2：

Project Number
S100
S200
S200
S300
S300
S300
S500

现在我必须将 Output1 和 Output2 转换为以下格式：

Output 1 :                          Output 2 :
Project Number    Count            Project Number    Count
S100              2                S100              1    
S200              1                S200              2   
S300              3                S300              3
S400              2                S500              1

现在匹配输出 1 和输出 2 并打印差异-

最终输出：

Project Number
S100
S200
S400
S500

Answer 1

WITH
-- first query, UNION ALL used instead of single UNION 
cte1 AS (select `Project Number` from vw_onco_pharma onco_pharma 
         union all
         select `Project Number` from vw_onco_cell_gene cell_gene 
         union all
         select `Project Number` from vw_non_onco_cell_gene onco_cell_gene 
         union all
         select `Project Number` from vw_non_onco_pharma non_onco_pharma 
         union all
         select `Project Number` from vw_plasma_protein plasma_protein),
-- count the amounts for 1st query
cte2 AS (SELECT `Project Number`, COUNT(*) cnt
         FROM cte1
         GROUP BY `Project Number`),
-- 2nd query, amounts counting added
cte3 AS (select `Project Number`, COUNT(*) cnt
         from FCT_HTA_ONC_NONONC_PGMS
         GROUP BY `Project Number`),
-- gathering all projects
cte4 AS (SELECT `Project Number`
         FROM cte1
         UNION 
         SELECT `Project Number`
         FROM cte3)
-- get final data
SELECT `Project Number`
FROM cte4
LEFT JOIN cte2 USING (`Project Number`)
LEFT JOIN cte4 USING (`Project Number`)
WHERE cte2.cnt IS NULL
   OR cte4.cnt IS NULL
   OR cte2.cnt <> cte4.cnt;

如何连接两个查询结果并根据条件过滤掉数据？

How to join two query result and filter out the data based on the condition?

mysql

sql

database

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