获取上周有价格更新的产品

Question

这是我的table历史：

productnr    price     changedate
1001           5         06.05.2020
1001           9         01.10.2021
1001           10        08.10.2021
1002           6         01.04.2021
1002           7         14.05.2021
1002           14        07.10.2021

我需要所有上周价格变化且最新价格与新价格之间的差异超过 15% 的产品。

想要的结果：

productnr     newprice    oldprice       last_changedate    secondlast_changedate 
1002          14            7                07.10.2021      14.05.2021

通过这个 SQL 查询，我得到了上周价格发生变化的所有产品：

Select *
from history
where TO_CHAR(changedate, 'iw') = TO_CHAR(next_day(trunc(sysdate+2), 'MONDAY') - 14, 'iw')
      and changedate > sysdate - 14

但是我不知道怎样才能达到我想要的结果。

Answer 1

您可以使用解析函数来查找以前的值：

如果你想比较最新的 productnr 和以前的：

SELECT *
FROM   (
  SELECT h.*,
         LEAD(price     ) OVER (PARTITION BY productnr ORDER BY changedate DESC) AS oldprice,
         LEAD(changedate) OVER (PARTITION BY productnr ORDER BY changedate DESC) AS oldchangedate,
         ROW_NUMBER() OVER (PARTITION BY productnr ORDER BY changedate DESC) AS rn
  FROM   history h
  WHERE  changedate > TRUNC(SYSDATE, 'IW') - INTERVAL '7' DAY
)
WHERE  (price < oldprice * (1 - 0.15) OR price > oldprice * (1 + 0.15))
AND    rn = 1;

或者，如果您想比较本周 productnr 的第一个 price 和上周的最后一个 price：

SELECT *
FROM   (
  SELECT h.*,
         LEAD(price     ) OVER (PARTITION BY productnr ORDER BY changedate DESC) AS oldprice,
         LEAD(changedate) OVER (PARTITION BY productnr ORDER BY changedate DESC) AS oldchangedate
  FROM   history h
  WHERE  changedate >= TRUNC(SYSDATE, 'IW') - INTERVAL '7' DAY
  AND    changedate <  TRUNC(SYSDATE, 'IW') + INTERVAL '7' DAY
)
WHERE  (price < oldprice * (1 - 0.15) OR price > oldprice * (1 + 0.15))
AND    changedate    >= TRUNC(SYSDATE, 'IW')
AND    oldchangedate <  TRUNC(SYSDATE, 'IW');

获取上周有价格更新的产品

Get products which had a price update last week

sql

oracle

oracle12c