替换 JSON 文件中的值

Question

我是 PowerShell 的新手。我有三个文件 output1.txt, output2.txt, deployer.json

output1.txt

db-tenant.rds.amazonaws.com

output2.txt

dev-51-db-global.rds.amazonaws.com

deployer.json

{
"user":"some_user",
"url":"some_url"
"urlglobal":"some_global_url",
"db":"some_db"
}

期望输出

{
"user":"some_user",
"url":"db-tenant.rds.amazonaws.com"
"urlglobal":"dev-51-db-global.rds.amazonaws.com",
"db":"some_db"
}

我想从 output1.txt 中获取结果并替换 url 中的值 deployer.json 文件

我也想从output2.txt中获取结果并用urlglobal[=48=中的值替换它] 在 deployer.json 文件中

这是我开始使用的脚本

脚本.ps1

$templatecontent = Get-Content -Path .\deployer.json

Answer 1

这很简单，希望代码是不言自明的。

$json = Get-Content path\to\deployer.json | ConvertFrom-Json

$json.url = Get-Content 'path\to\output1.txt'
$json.urlglobal = Get-Content 'path\to\output2.txt'

如果您想在不使用外部文件的情况下测试代码：

$url = 'db-tenant.rds.amazonaws.com'
$urlglobal = 'dev-51-db-global.rds.amazonaws.com'

$json = @'
{
"user":"some_user",
"url":"some_url",
"urlglobal":"some_global_url",
"db":"some_db"
}
'@ | ConvertFrom-Json

$json.url = $url
$json.urlglobal = $urlglobal

然后$json | ConvertTo-Json输出：

{
    "user":  "some_user",
    "url":  "db-tenant.rds.amazonaws.com",
    "urlglobal":  "dev-51-db-global.rds.amazonaws.com",
    "db":  "some_db"
}

替换 JSON 文件中的值

Replace Values in a JSON file

powershell

amazon-web-services

aws-cli