使用多个文字定界符在 R 中的数据框中拆分字符串

Splitting a string in a dataframe in R using multiple literal delimiters

我有一个单列地址数据框,如下所示:

ADDRESS
123 Main Street Unit A
456 Main Street Apt 3
789 Main Street Floor 2

我想解析地址以将 Unit/Apt/Floor 信息与街道地址的其余部分分开。有没有一种简单的方法可以做到这一点,一开始就知道分隔符应该是“Unit”、“Apt”和“Floor”?

所需的最终结果将是一个两列的数据框,如下所示:

ADDRESS           UNIT
123 Main Street   Unit A
456 Main Street   Apt 3
789 Main Street   Floor 2

我试过使用 tidyr 包中的 separate,但它只接受(据我所知)一个分隔符参数。因此,可以通过多次调用 separate 来完成此任务,但这看起来很愚蠢。

df <- df %>% tidyr::separate(ADDRESS, into = c("ADDRESS","UNIT"), sep = ' Apt')
# This would need to repeated using ' Unit' and ' Floor'.

同样,似乎 stringr::str_split_fixed() 应该能够处理这个任务,但我还是想不出如何通过一次调用完成这个过程(即一次指定三个分隔符)。

stringr::str_split_fixed(df$Address, c(' Unit', ' Apt', ' Floor'), 2)
# Does not work! Additionally does not result in additional column in dataframe as desired.

这是创建示例数据框的代码:

library(dplyr)    # for piping
library(tidyr)
library(stringr)

df <- data.frame(ADDRESS = c("123 Main Street Unit A", "456 Main Street Apt 3", "789 Main Street Floor 2"))

这个有用吗:

使用基数 R:

gsub('(\d+\sMain Street\s)(.*)','\2',df$ADDRESS)
[1] "Unit A"  "Apt 3"   "Floor 2"

使用 dplyr 和 stringr:

library(dplyr)
library(stringr)
df %>% mutate(UNIT = str_extract(ADDRESS, '(?<=Main Street ).*'))
                  ADDRESS    UNIT
1  123 Main Street Unit A  Unit A
2   456 Main Street Apt 3   Apt 3
3 789 Main Street Floor 2 Floor 2

使用 tidyr::separate 你可以:

library(tidyr)

df <- data.frame(ADDRESS = c("123 Main Street Unit A", "456 Main Street Apt 3", "789 Main Street Floor 2"))
df %>% 
  separate(ADDRESS, sep = "\s(?=Unit|Apt|Floor)", into = c("address", "unit"))
#>           address    unit
#> 1 123 Main Street  Unit A
#> 2 456 Main Street   Apt 3
#> 3 789 Main Street Floor 2

这对基础 R 也有帮助:

df$UNIT <- trimws(regmatches(df$ADDRESS, regexpr("\d+\s+Main\s+Street\K(.*)", df$ADDRESS, perl = TRUE)))

                  ADDRESS    UNIT
1  123 Main Street Unit A  Unit A
2   456 Main Street Apt 3   Apt 3
3 789 Main Street Floor 2 Floor 2