以十六进制格式处理时数字大小丢失

Question

处理十六进制数时遇到问题。当文件中的运行 str (hex ()) 时，0x... 之后的零消失。

入口处：

0x0000000000000000000000000000000000000000000000000000000000000001f01f80f12f7cf16638f7a8074d46fe2f421a73432b1441a01ed3dd883c68acad
0x00000000000000000000000000000000000000000000000000000000000000029a799033fc54073346f870c15c9836f6b2e9eccdb85f09d29a8ddc90dc3a8ef1
0x00000000000000000000000000000000000000000000000000000000000000033e561483073e429ec25c09c99de2a81d5a34a539ad2dbb688af6b6f5f24936a4

退出时：

0x1f01f80f12f7cf16638f7a8074d46fe2f421a73432b1441a01ed3dd883c68acad
0x29a799033fc54073346f870c15c9836f6b2e9eccdb85f09d29a8ddc90dc3a8ef1
0x33e561483073e429ec25c09c99de2a81d5a34a539ad2dbb688af6b6f5f24936a4

代码：

   with open("data.txt", "r") as file:
        for line in file:
            L = int(line, 0)
            R = str(hex(L))
            print(R)

代码中需要修复什么？我需要一种大小的数字并且不丢失零。

Answer 1

使用字符串格式：

# 表示将 0x 放在十六进制数字的前面。
0130 表示字段长度为 130 个字符，前导零表示用零填充。
x表示十六进制（小写a-f）。

line = '0x0000000000000000000000000000000000000000000000000000000000000001f01f80f12f7cf16638f7a8074d46fe2f421a73432b1441a01ed3dd883c68acad'
print(line)  # as read from file
integer = int(line, 0)
formatted = f'{integer:#0130x}'
print(formatted)
print(formatted == line) # check that original and re-formatted are the same

输出：

0x0000000000000000000000000000000000000000000000000000000000000001f01f80f12f7cf16638f7a8074d46fe2f421a73432b1441a01ed3dd883c68acad
0x0000000000000000000000000000000000000000000000000000000000000001f01f80f12f7cf16638f7a8074d46fe2f421a73432b1441a01ed3dd883c68acad
True

以十六进制格式处理时数字大小丢失

Loss of size of numbers when processing in hex format

python

hex

numbers

list

python-3.x