我正在尝试 return 只是截止日期和发布日期之间的天数。然而，它也是 return 时分秒

Question

这是我目前的代码：

import pandas as pd

df = pd.read_csv('/content/drive/MyDrive/Colab Datasets/KickstarterRevised.csv')
df['deadline'] = pd.to_datetime(df['deadline'])
df['launched'] =  pd.to_datetime(df['launched'])

df['difference'] = df['deadline'].sub(df['launched'], axis=0)
df['difference']

0      58 days 23:24:00
1      45 days 00:00:00
2      30 days 01:00:00
3      55 days 16:25:00
4      35 days 00:00:00
             ...       
4994   40 days 00:00:00
4995    8 days 10:50:00
4996   38 days 18:53:00
4997   30 days 00:00:00
4998   30 days 00:00:00
Name: difference, Length: 4999, dtype: timedelta64[ns]

Answer 1

正如您从代码中看到的，df['difference'] 是一个带有 dtype: timedelta64[ns] 的系列。要获取天数，只需使用.astype("timedelta64[D]")，见下文

df['difference'] = df['deadline'].sub(df['launched'], axis=0).astype('timedelta64[D]')

我正在尝试 return 只是截止日期和发布日期之间的天数。然而，它也是 return 时分秒

I am trying to return just the amount of days between deadline and launch date. However it is returning the hours minutes and seconds as well

python

pandas

datetime

date-difference