如何解决终端消息中的分段错误?
how can i solve segmentation error in terminal message?
我写了一个简单的程序来从用户那里获取姓名和数字并将其存储在一个数组中,然后在每个单元格之间进行比较直到达到最高等级然后显示它。问题是当它 运行 它显示一条消息(分段错误(核心转储))。我真的不知道我的错误是什么。
#include <stdio.h>
int main() {
int n;
printf("Enter the number of students: ");
scanf("%d", & n);
char name[n];
float score[n];
for (int i = 0; i < n; i++) {
printf("\nEnter the name of Student: ");
scanf("%s", & name[i]);
printf("\nEnter the score: ");
scanf("%f", & score[i]);
}
float max;
int index;
max = score[0];
index = 0;
for (int i = 1; i < n; i++) {
if (max < score[i]) {
max = score[i];
index = i;
}
}
printf("\nHighest mark scored is %f by student %s", name[index], score[index]);
}
1- you use user input to define the size of an array (wrong)
-- array in c has static size so you must define it's size before the code reach the compiling stage(use dynamic memory allocation instead)
2- scanf("%s", & name[I]); you want to save array of char and save the address at the name variable but name it self not a pointer to save address it's just of char type (wrong)
-- you need pointer to save the address of every name so it's array of pointer and a pointer to allocate the address of the array to it so it's a pointer to poiner and define max size of word if you define size the user input exceed it will produce an error
3- finally you exchanged the %f,%s in printf
#include <stdlib.h>
#include <stdio.h>
#define SIZE_OF_WORD 10
int main() {
int n;
printf("Enter the number of students: ");
scanf("%d", & n);
char **name=(char**)malloc((sizeof(char*)*n));
for (int i = 0; i < n; i++) {
name[i]=(char*)malloc((sizeof(char)*SIZE_OF_WORD));
}
float *score=(float*)malloc((sizeof(float)*n));
for (int i = 0; i < n; i++) {
printf("\nEnter the name of Student: ");
scanf("%s", name[i]);
printf("\nEnter the score: ");
scanf("%f", & score[i]);
}
float max;
int index;
max = score[0];
index = 0;
for (int i = 1; i < n; i++) {
if (max < score[i]) {
max = score[i];
index = i;
}
}
printf("\nHighest mark scored is %s by student %.0f\n", name[index],score[index]);
}
我写了一个简单的程序来从用户那里获取姓名和数字并将其存储在一个数组中,然后在每个单元格之间进行比较直到达到最高等级然后显示它。问题是当它 运行 它显示一条消息(分段错误(核心转储))。我真的不知道我的错误是什么。
#include <stdio.h>
int main() {
int n;
printf("Enter the number of students: ");
scanf("%d", & n);
char name[n];
float score[n];
for (int i = 0; i < n; i++) {
printf("\nEnter the name of Student: ");
scanf("%s", & name[i]);
printf("\nEnter the score: ");
scanf("%f", & score[i]);
}
float max;
int index;
max = score[0];
index = 0;
for (int i = 1; i < n; i++) {
if (max < score[i]) {
max = score[i];
index = i;
}
}
printf("\nHighest mark scored is %f by student %s", name[index], score[index]);
}
1- you use user input to define the size of an array (wrong)
-- array in c has static size so you must define it's size before the code reach the compiling stage(use dynamic memory allocation instead)
2- scanf("%s", & name[I]); you want to save array of char and save the address at the name variable but name it self not a pointer to save address it's just of char type (wrong)
-- you need pointer to save the address of every name so it's array of pointer and a pointer to allocate the address of the array to it so it's a pointer to poiner and define max size of word if you define size the user input exceed it will produce an error
3- finally you exchanged the %f,%s in printf
#include <stdlib.h>
#include <stdio.h>
#define SIZE_OF_WORD 10
int main() {
int n;
printf("Enter the number of students: ");
scanf("%d", & n);
char **name=(char**)malloc((sizeof(char*)*n));
for (int i = 0; i < n; i++) {
name[i]=(char*)malloc((sizeof(char)*SIZE_OF_WORD));
}
float *score=(float*)malloc((sizeof(float)*n));
for (int i = 0; i < n; i++) {
printf("\nEnter the name of Student: ");
scanf("%s", name[i]);
printf("\nEnter the score: ");
scanf("%f", & score[i]);
}
float max;
int index;
max = score[0];
index = 0;
for (int i = 1; i < n; i++) {
if (max < score[i]) {
max = score[i];
index = i;
}
}
printf("\nHighest mark scored is %s by student %.0f\n", name[index],score[index]);
}